Wave Properties and Types

Progressive and stationary waves; longitudinal vs transverse; intensity ∝ A²

# Wave Properties and Types — A-Level Physics

Waves transfer energy without transferring matter. At A-Level, you need to understand wave properties quantitatively, distinguish between progressive and stationary waves, and relate intensity to amplitude.


1. Progressive Waves

A progressive wave carries energy from one point to another. Each point on the wave oscillates about its equilibrium position.

Properties

  • Amplitude (AA): Maximum displacement from equilibrium
  • Wavelength (λ\lambda): Distance between consecutive points in phase
  • Frequency (ff): Number of complete oscillations per second (Hz)
  • Period (TT): Time for one complete oscillation; T=1/fT = 1/f
  • Wave speed: v=fλv = f\lambda
  • Phase difference (Δϕ\Delta\phi): Measured in radians or degrees. Points one wavelength apart have Δϕ=2π\Delta\phi = 2\pi

Δϕ=2πxλ\Delta\phi = \frac{2\pi x}{\lambda}

where xx is the path difference.

Wave Equation

y=Asin(ωtkx)y = A\sin(\omega t - kx)

Where:

  • ω=2πf\omega = 2\pi f = angular frequency
  • k=2π/λk = 2\pi/\lambda = wave number
  • The minus sign indicates the wave travels in the positive x-direction

2. Transverse vs Longitudinal

Transverse: Oscillations perpendicular to direction of propagation. Can be polarised.

  • EM waves, water surface waves, waves on strings, S-waves

Longitudinal: Oscillations parallel to direction of propagation. Cannot be polarised.

  • Sound, ultrasound, P-waves, compression waves in springs

3. Intensity

Intensity is the power transmitted per unit area:

I=PAarea\boxed{I = \frac{P}{A_{\text{area}}}}

Units: W/m²

For a wave: intensity is proportional to amplitude squared:

IA2I \propto A^2

If amplitude doubles, intensity quadruples.

For a point source radiating equally in all directions: I=P4πr2I = \frac{P}{4\pi r^2}

This gives the inverse square law: I1/r2I \propto 1/r^2.


4. Polarisation

Polarisation restricts the oscillations of a transverse wave to a single plane.

  • Only transverse waves can be polarised
  • This proves light is transverse (since it can be polarised)
  • A polariser (Polaroid filter) only transmits oscillations in one plane
  • Two polarisers at 90° block all light

Malus's Law

When polarised light of intensity I0I_0 passes through a second polariser (analyser) at angle θ\theta:

I=I0cos2θI = I_0 \cos^2\theta

Applications

  • Polarising sunglasses (reduce glare from reflected light)
  • LCD screens
  • Stress analysis in engineering
  • Radio/TV antenna alignment

5. Electromagnetic Waves

All EM waves:

  • Travel at c=3×108c = 3 \times 10^8 m/s in vacuum
  • Are transverse
  • Can be polarised
  • Consist of oscillating electric and magnetic fields
  • c=fλc = f\lambda

Spectrum: Radio → Microwave → IR → Visible → UV → X-ray → Gamma


Worked Example: Example 1

Problem

A wave has frequency 500 Hz and wavelength 0.68 m. Find the wave speed and the phase difference between points 0.17 m apart.

v=fλ=500×0.68=340v = f\lambda = 500 \times 0.68 = 340 m/s Δϕ=2πx/λ=2π(0.17)/0.68=π/2\Delta\phi = 2\pi x/\lambda = 2\pi(0.17)/0.68 = \pi/2 rad = 90°

Solution

Worked Example: Example 2

Problem

The intensity of sound 2 m from a speaker is 0.5 W/m². Find the intensity at 8 m.

I1/r2I \propto 1/r^2: I2=I1(r1/r2)2=0.5×(2/8)2=0.5×1/16=0.03125I_2 = I_1(r_1/r_2)^2 = 0.5 \times (2/8)^2 = 0.5 \times 1/16 = 0.03125 W/m²

Solution

Worked Example: Malus's Law

Problem

Polarised light of intensity 200 W/m² passes through a polariser at 30°. Find the transmitted intensity.

I=200cos230°=200×0.75=150I = 200\cos^2 30° = 200 \times 0.75 = 150 W/m²


Solution

7. Practice Questions

    1. A radio wave has f=100f = 100 MHz. Calculate its wavelength. (1 mark)
    1. The amplitude of a wave is halved. By what factor does the intensity change? (1 mark)
    1. Two points on a wave are 0.3λ apart. Calculate their phase difference in radians. (2 marks)
    1. Unpolarised light passes through two polarisers with axes at 60° to each other. The initial intensity is I0I_0. Find the final intensity. (3 marks)

    Answers

    1. λ=c/f=3×108/108=3\lambda = c/f = 3 \times 10^8/10^8 = 3 m.

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Summary

  • Progressive waves carry energy; described by y=Asin(ωtkx)y = A\sin(\omega t - kx)
  • v=fλv = f\lambda; ω=2πf\omega = 2\pi f; k=2π/λk = 2\pi/\lambda
  • IA2I \propto A^2; for point source I1/r2I \propto 1/r^2
  • Only transverse waves can be polarised
  • Malus's Law: I=I0cos2θI = I_0\cos^2\theta

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