The Normal Distribution

Work with the normal distribution at A-Level. Standardise, find probabilities, and use inverse normal.

The normal distribution XN(μ,σ2)X \sim N(\mu, \sigma^2) is the most important continuous distribution. Its bell-shaped curve models many natural phenomena.

Core Concepts

Properties

  • Symmetric about μ\mu.
  • Total area under curve = 1.
  • ~68% within 1σ, ~95% within 2σ, ~99.7% within 3σ.

Standardising

Z=XμσZ = \frac{X - \mu}{\sigma}

Converts XN(μ,σ2)X \sim N(\mu, \sigma^2) to ZN(0,1)Z \sim N(0, 1) (standard normal).

Finding Probabilities

P(X<a)=P(Z<aμσ)P(X < a) = P\left(Z < \frac{a - \mu}{\sigma}\right). Look up in tables or use calculator.

Inverse Normal

Given a probability, find the value of xx.

If P(X<a)=0.95P(X < a) = 0.95, standardise: aμσ=1.645\frac{a - \mu}{\sigma} = 1.645a=μ+1.645σa = \mu + 1.645\sigma.

Worked Example: Example 1

Problem

XN(50,16)X \sim N(50, 16) (so σ=4\sigma = 4). Find P(X>56)P(X > 56).

Z=56504=1.5Z = \frac{56-50}{4} = 1.5. P(Z>1.5)=10.9332=0.0668P(Z > 1.5) = 1 - 0.9332 = 0.0668.

Solution

Worked Example: Example 2

Problem

XN(100,225)X \sim N(100, 225). Find aa such that P(X<a)=0.9P(X < a) = 0.9.

σ=15\sigma = 15. Z=1.2816Z = 1.2816. a=100+1.2816(15)=119.2a = 100 + 1.2816(15) = 119.2.

Solution

Practice Problems

    1. XN(70,25)X \sim N(70, 25). Find P(65<X<75)P(65 < X < 75).
    1. Find σ\sigma if P(X>80)=0.1P(X > 80) = 0.1 and μ=60\mu = 60.
    1. Approximate B(100,0.4)B(100, 0.4) using a normal distribution.

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Key Takeaways

  • Z=XμσZ = \frac{X - \mu}{\sigma} standardises.

  • Use tables/calculator for P(Z<z)P(Z < z).

  • Inverse normal: given probability, find xx.

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