The R-Formula (Harmonic Form)

Write a cos θ + b sin θ in the form R cos(θ ± α) or R sin(θ ± α) at A-Level.

The R-formula converts acos⁡θ+bsin⁡θa\cos\theta + b\sin\theta into a single trig function Rcos⁡(θ±α)R\cos(\theta \pm \alpha) or Rsin⁡(θ±α)R\sin(\theta \pm \alpha). This makes it possible to find max/min values and solve equations.

The Formula

acos⁡θ+bsin⁡θ=Rcos⁡(θ−α)a\cos\theta + b\sin\theta = R\cos(\theta - \alpha)

where R=a2+b2R = \sqrt{a^2 + b^2} and tan⁡α=ba\tan\alpha = \frac{b}{a}.

Method

  1. Expand Rcos⁡(θ−α)=Rcos⁡θcos⁡α+Rsin⁡θsin⁡αR\cos(\theta - \alpha) = R\cos\theta\cos\alpha + R\sin\theta\sin\alpha.
  2. Compare coefficients: Rcos⁡α=aR\cos\alpha = a, Rsin⁡α=bR\sin\alpha = b.
  3. R=a2+b2R = \sqrt{a^2 + b^2}, tan⁡α=ba\tan\alpha = \frac{b}{a}.

Maximum and Minimum

Rcos⁡(θ−α)R\cos(\theta - \alpha) has max RR (when θ=α\theta = \alpha) and min −R-R (when θ=α+π\theta = \alpha + \pi).

Worked Example

Write 3cos⁡θ+4sin⁡θ3\cos\theta + 4\sin\theta in the form Rcos⁡(θ−α)R\cos(\theta - \alpha).

R=9+16=5R = \sqrt{9 + 16} = 5. tan⁡α=43\tan\alpha = \frac{4}{3} → α=53.13°\alpha = 53.13°.

3cos⁡θ+4sin⁡θ=5cos⁡(θ−53.13°)3\cos\theta + 4\sin\theta = 5\cos(\theta - 53.13°).

Max = 5, min = −5.

Solving Equations

3cos⁡θ+4sin⁡θ=23\cos\theta + 4\sin\theta = 2 → 5cos⁡(θ−53.13°)=25\cos(\theta - 53.13°) = 2 → cos⁡(θ−53.13°)=0.4\cos(\theta - 53.13°) = 0.4.

θ−53.13°=±66.42°\theta - 53.13° = \pm 66.42° → θ=119.55°\theta = 119.55° or θ=−13.29°\theta = -13.29° (+ 360°).

Practice Problems

    1. Write 5sin⁡θ+12cos⁡θ5\sin\theta + 12\cos\theta in the form Rsin⁡(θ+α)R\sin(\theta + \alpha).
    1. Find the maximum value of 2cos⁡θ+sin⁡θ2\cos\theta + \sin\theta.
    1. Solve 3cos⁡θ+sin⁡θ=1\sqrt{3}\cos\theta + \sin\theta = 1 for 0≤θ≤360°0 \leq \theta \leq 360°.

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Key Takeaways

  • ✓

    R=a2+b2R = \sqrt{a^2 + b^2}. tan⁡α=ba\tan\alpha = \frac{b}{a}.

  • ✓

    Max/min of the expression: ±R\pm R.

  • ✓

    Enables solving equations that combine sin and cos.

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