The R-Formula (Harmonic Form)

Write a cos θ + b sin θ in the form R cos(θ ± α) or R sin(θ ± α) at A-Level.

The R-formula converts acosθ+bsinθa\cos\theta + b\sin\theta into a single trig function Rcos(θ±α)R\cos(\theta \pm \alpha) or Rsin(θ±α)R\sin(\theta \pm \alpha). This makes it possible to find max/min values and solve equations.

The Formula

acosθ+bsinθ=Rcos(θα)a\cos\theta + b\sin\theta = R\cos(\theta - \alpha)

where R=a2+b2R = \sqrt{a^2 + b^2} and tanα=ba\tan\alpha = \frac{b}{a}.

Method

  1. Expand Rcos(θα)=Rcosθcosα+RsinθsinαR\cos(\theta - \alpha) = R\cos\theta\cos\alpha + R\sin\theta\sin\alpha.
  2. Compare coefficients: Rcosα=aR\cos\alpha = a, Rsinα=bR\sin\alpha = b.
  3. R=a2+b2R = \sqrt{a^2 + b^2}, tanα=ba\tan\alpha = \frac{b}{a}.

Maximum and Minimum

Rcos(θα)R\cos(\theta - \alpha) has max RR (when θ=α\theta = \alpha) and min R-R (when θ=α+π\theta = \alpha + \pi).

Worked Example

Write 3cosθ+4sinθ3\cos\theta + 4\sin\theta in the form Rcos(θα)R\cos(\theta - \alpha).

R=9+16=5R = \sqrt{9 + 16} = 5. tanα=43\tan\alpha = \frac{4}{3}α=53.13°\alpha = 53.13°.

3cosθ+4sinθ=5cos(θ53.13°)3\cos\theta + 4\sin\theta = 5\cos(\theta - 53.13°).

Max = 5, min = −5.

Solving Equations

3cosθ+4sinθ=23\cos\theta + 4\sin\theta = 25cos(θ53.13°)=25\cos(\theta - 53.13°) = 2cos(θ53.13°)=0.4\cos(\theta - 53.13°) = 0.4.

θ53.13°=±66.42°\theta - 53.13° = \pm 66.42°θ=119.55°\theta = 119.55° or θ=13.29°\theta = -13.29° (+ 360°).

Practice Problems

    1. Write 5sinθ+12cosθ5\sin\theta + 12\cos\theta in the form Rsin(θ+α)R\sin(\theta + \alpha).
    1. Find the maximum value of 2cosθ+sinθ2\cos\theta + \sin\theta.
    1. Solve 3cosθ+sinθ=1\sqrt{3}\cos\theta + \sin\theta = 1 for 0θ360°0 \leq \theta \leq 360°.

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Key Takeaways

  • R=a2+b2R = \sqrt{a^2 + b^2}. tanα=ba\tan\alpha = \frac{b}{a}.

  • Max/min of the expression: ±R\pm R.

  • Enables solving equations that combine sin and cos.

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