Exponentials and Logarithms

Master exponential and logarithmic functions at A-Level. Apply log laws, solve equations, and work with e and ln.

Exponentials and logarithms are inverse operations. The natural exponential exe^x and natural log ln⁡x\ln x are central to A-Level Maths.

Core Concepts

Log Laws

log⁡a(xy)=log⁡ax+log⁡ay\log_a(xy) = \log_a x + \log_a y log⁡a(xy)=log⁡ax−log⁡ay\log_a\left(\frac{x}{y}\right) = \log_a x - \log_a y log⁡a(xn)=nlog⁡ax\log_a(x^n) = n\log_a x log⁡aa=1,log⁡a1=0\log_a a = 1, \quad \log_a 1 = 0

Change of Base

log⁡ax=log⁡bxlog⁡ba\log_a x = \frac{\log_b x}{\log_b a}

The Natural Exponential

e≈2.71828...e \approx 2.71828.... ddx(ex)=ex\frac{d}{dx}(e^x) = e^x.

ln⁡x=log⁡ex\ln x = \log_e x. eln⁡x=xe^{\ln x} = x and ln⁡(ex)=x\ln(e^x) = x.

Solving Exponential Equations

3x=203^x = 20 → xln⁡3=ln⁡20x\ln 3 = \ln 20 → x=ln⁡20ln⁡3≈2.73x = \frac{\ln 20}{\ln 3} \approx 2.73.

Solving Logarithmic Equations

2ln⁡x−ln⁡(x+1)=ln⁡32\ln x - \ln(x+1) = \ln 3 → ln⁡x2x+1=ln⁡3\ln\frac{x^2}{x+1} = \ln 3 → x2x+1=3\frac{x^2}{x+1} = 3 → x2=3x+3x^2 = 3x + 3 → x2−3x−3=0x^2 - 3x - 3 = 0.

Modelling

y=abty = ab^t → ln⁡y=ln⁡a+tln⁡b\ln y = \ln a + t\ln b (straight line with gradient ln⁡b\ln b).

Practice Problems

    1. Solve 52x=85^{2x} = 8.
    1. Simplify ln⁡(e3)+ln⁡(e−1)\ln(e^3) + \ln(e^{-1}).
    1. Solve log⁡2(x+3)+log⁡2(x)=5\log_2(x+3) + \log_2(x) = 5.

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Key Takeaways

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    Log laws convert between products/powers and sums.

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    ln⁡\ln and ee are inverses.

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    Take logs to solve exponential equations.

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    Exponentiate to solve logarithmic equations.

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    State the range of validity (logs of positive numbers only).

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