Binomial Expansion

Expand expressions using the binomial theorem at A-Level. Apply for positive integer powers and general binomial expansions.

The binomial theorem provides a formula for expanding (a+b)n(a + b)^n. At A-Level, you need both the standard expansion for positive integers and the general expansion for rational powers.

For Positive Integer $n$

(a+b)n=r=0n(nr)anrbr(a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r

(nr)=n!r!(nr)!\binom{n}{r} = \frac{n!}{r!(n-r)!}

Example

(1+x)4=1+4x+6x2+4x3+x4(1 + x)^4 = 1 + 4x + 6x^2 + 4x^3 + x^4

(2+3x)3=8+36x+54x2+27x3(2 + 3x)^3 = 8 + 36x + 54x^2 + 27x^3

Finding a Specific Term

The (r+1)(r+1)th term: (nr)anrbr\binom{n}{r} a^{n-r} b^r.

General Binomial Expansion ($n$ not a positive integer)

(1+x)n=1+nx+n(n1)2!x2+n(n1)(n2)3!x3+...(1 + x)^n = 1 + nx + \frac{n(n-1)}{2!}x^2 + \frac{n(n-1)(n-2)}{3!}x^3 + ...

Valid for x<1|x| < 1.

Example

(1+x)1=1x+x2x3+...(1 + x)^{-1} = 1 - x + x^2 - x^3 + ...

(1+x)12=1+12x18x2+116x3...(1 + x)^{\frac{1}{2}} = 1 + \frac{1}{2}x - \frac{1}{8}x^2 + \frac{1}{16}x^3 - ...

For (a+bx)n(a + bx)^n

Factor out ana^n: an(1+bxa)na^n(1 + \frac{bx}{a})^n, then expand, valid for bxa<1|\frac{bx}{a}| < 1.

Worked Example: Example 1

Problem

Expand (12x)3(1 - 2x)^{-3} up to x2x^2.

=1+(3)(2x)+(3)(4)2(2x)2+...= 1 + (-3)(-2x) + \frac{(-3)(-4)}{2}(-2x)^2 + ... =1+6x+24x2+...= 1 + 6x + 24x^2 + ...

Valid for 2x<1|2x| < 1, i.e., x<12|x| < \frac{1}{2}.

Solution

Practice Problems

    1. Expand (2+x)5(2 + x)^5.
    1. Find the coefficient of x3x^3 in (13x)8(1 - 3x)^8.
    1. Expand (1+4x)12(1 + 4x)^{\frac{1}{2}} up to x3x^3 and state validity.

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Key Takeaways

  • Integer nn: use (nr)\binom{n}{r}, finite expansion.

  • General nn: infinite series, valid for x<1|x| < 1.

  • For (a+bx)n(a+bx)^n: factor out ana^n first.

  • State the range of validity.

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