Alkenes and Addition Reactions

Master electrophilic addition, Markovnikov's rule, E/Z isomerism, and polymerisation for A-Level Chemistry.

# Alkenes and Addition Reactions

Alkenes are unsaturated hydrocarbons with a C=C double bond, making them much more reactive than alkanes. Their key reaction is electrophilic addition, where molecules add across the double bond. Understanding the mechanism, including Markovnikov's rule, is essential for A-Level Chemistry.


1. Structure of Alkenes

  • General formula: CnH2nC_nH_{2n}
  • Contain a C=C double bond (one σ bond + one π bond)
  • The π bond is a region of high electron density above and below the plane of the molecule
  • This electron-rich area attracts electrophiles

E/Z Isomerism (Geometric Isomerism)

Occurs when:

  1. There is a C=C double bond (no rotation)
  2. Each carbon of the double bond has two different groups

Naming uses Cahn-Ingold-Prelog priority rules (based on atomic number):

  • Z (zusammen = together): higher priority groups on the same side
  • E (entgegen = opposite): higher priority groups on opposite sides

2. Electrophilic Addition

What Is an Electrophile?

An electrophile is an electron-pair acceptor — it's attracted to electron-rich regions (like the C=C π bond).

General Mechanism

  1. The electrophile is attracted to the π bond electron density
  2. The π bond breaks and one pair of electrons forms a new bond to the electrophile
  3. A carbocation intermediate forms
  4. A nucleophile attacks the carbocation to complete the addition

2.1 Addition of Hydrogen Halides (HBr)

CH2=CH2+HBrCH3CH2Br\text{CH}_2\text{=CH}_2 + \text{HBr} \rightarrow \text{CH}_3\text{CH}_2\text{Br}

Mechanism:

  1. The H-Br bond is polar (Hδ+\text{H}^{\delta+}, Brδ\text{Br}^{\delta-})
  2. Hδ+\text{H}^{\delta+} is attracted to the electron-rich C=C
  3. A curly arrow from the C=C π bond to the H
  4. The H-Br bond breaks heterolytically → H bonds to one carbon, Br⁻ is released
  5. A carbocation forms on the other carbon
  6. Br⁻ attacks the carbocation (curly arrow from Br⁻ to C⁺)

2.2 Markovnikov's Rule

With unsymmetrical alkenes (like propene), two products are possible:

CH3CH=CH2+HBr{CH3CHBrCH3(major)CH3CH2CH2Br(minor)\text{CH}_3\text{CH=CH}_2 + \text{HBr} \rightarrow \begin{cases} \text{CH}_3\text{CHBrCH}_3 & \text{(major)} \\ \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} & \text{(minor)} \end{cases}

Markovnikov's rule: The hydrogen adds to the carbon with more existing H atoms (or equivalently, the halide goes to the more substituted carbon).

Why? The secondary carbocation (CH3C+HCH3\text{CH}_3\text{C}^+\text{HCH}_3) is more stable than the primary carbocation (CH3CH2C+H2\text{CH}_3\text{CH}_2\text{C}^+\text{H}_2) due to the electron-donating (inductive) effect of alkyl groups.

2.3 Addition of Bromine (Br₂)

CH2=CH2+Br2CH2BrCH2Br\text{CH}_2\text{=CH}_2 + \text{Br}_2 \rightarrow \text{CH}_2\text{BrCH}_2\text{Br}

Bromine is non-polar, but the electron-rich C=C induces a dipole in Br₂. This is the test for alkenes (bromine water decolourises from orange to colourless).

2.4 Addition of Steam (Hydration)

CH2=CH2+H2OH3PO4,300°CCH3CH2OH\text{CH}_2\text{=CH}_2 + \text{H}_2\text{O} \xrightarrow{\text{H}_3\text{PO}_4, 300°\text{C}} \text{CH}_3\text{CH}_2\text{OH}

Produces ethanol. Used industrially.

2.5 Hydrogenation

CH2=CH2+H2Ni catalystCH3CH3\text{CH}_2\text{=CH}_2 + \text{H}_2 \xrightarrow{\text{Ni catalyst}} \text{CH}_3\text{CH}_3

Used to harden vegetable oils into margarine.


3. Addition Polymerisation

Many alkene monomers join to form a long-chain polymer: nCH2=CH2(CH2-CH2)nn\text{CH}_2\text{=CH}_2 \rightarrow (-\text{CH}_2\text{-CH}_2-)_n

Drawing Polymers

  • Open the C=C double bond to show single bonds extending from the repeat unit
  • Enclose in brackets with nn subscript
  • For substituted alkenes (e.g. propene, chloroethene), show the substituent in the repeat unit

Worked Example: Mechanism

Problem

Question: Draw the mechanism for the reaction of propene with HBr.

Solution
  1. H⁺ (δ+) attracted to C=C; curly arrow from C=C to H; H-Br breaks heterolytically
  2. Secondary carbocation forms on middle carbon (Markovnikov's rule)
  3. Br⁻ attacks carbocation → 2-bromopropane (major product)

Worked Example: E/Z Naming

Problem

Question: Name: CH₃CH=CHCl with Cl and CH₃ on the same side.

Solution

Higher priority groups: Cl > H on one C; CH₃ > H on the other C. Cl and CH₃ on same side = Z. Name: (Z)-1-chloropropene.


5. Practice Questions

    1. Draw the mechanism for the electrophilic addition of HBr to but-1-ene. Predict the major product.
    1. Explain why the secondary carbocation is more stable than the primary.
    1. What would you observe when bromine water is added to cyclohexene?
    1. Draw the repeat unit of poly(chloroethene) (PVC).
    1. Explain E/Z isomerism using but-2-ene as an example.

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6. Exam Tips

  • Always show curly arrows clearly in mechanisms (from electron-rich to electron-poor)
  • For Markovnikov's, remember: H goes to the C with more H's
  • E/Z isomerism: use priority rules based on atomic number
  • The test for alkenes: bromine water decolourises (orange → colourless)

Summary

  • Alkenes: CnH2nC_nH_{2n}, C=C double bond, unsaturated
  • E/Z isomerism due to restricted rotation around C=C
  • Electrophilic addition: HBr, Br₂, H₂O, H₂ add across C=C
  • Markovnikov's rule: major product has more stable carbocation intermediate
  • Addition polymerisation: many monomers → long polymer chain

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