Probability

AP Statistics guide to probability: basic rules, conditional probability, independence, Bayes' theorem, and counting principles.

# Probability — AP Statistics

Probability provides the mathematical framework for statistical inference. AP Statistics covers probability rules, conditional probability, independence, and the law of large numbers.

Key Concepts

Basic Probability

0P(A)10 \leq P(A) \leq 1 P(Ac)=1P(A)P(A^c) = 1 - P(A)

Addition Rule

P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B)

If AA and BB are mutually exclusive: P(AB)=P(A)+P(B)P(A \cup B) = P(A) + P(B).

Multiplication Rule

P(AB)=P(A)P(BA)P(A \cap B) = P(A) \cdot P(B|A)

If AA and BB are independent: P(AB)=P(A)P(B)P(A \cap B) = P(A) \cdot P(B).

Conditional Probability

P(BA)=P(AB)P(A)P(B|A) = \frac{P(A \cap B)}{P(A)}

Independence

Events AA and BB are independent if P(BA)=P(B)P(B|A) = P(B).

Law of Large Numbers

As the number of trials increases, the sample proportion approaches the true probability.

Two-Way Tables

Use two-way tables to find joint, marginal, and conditional probabilities.

Tree Diagrams

Useful for visualizing sequential events and computing conditional probabilities (Bayes' theorem).

Bayes' Theorem

P(AB)=P(BA)P(A)P(B)P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)}

Worked Example

Problem: In a class, 60% are female. Of females, 80% pass. Of males, 70% pass. Find P(pass)P(\text{pass}).

Solution: By the law of total probability: P(pass)=P(F)P(passF)+P(M)P(passM)P(\text{pass}) = P(F)P(\text{pass}|F) + P(M)P(\text{pass}|M) =0.6(0.8)+0.4(0.7)=0.48+0.28=0.76= 0.6(0.8) + 0.4(0.7) = 0.48 + 0.28 = 0.76

Practice Questions

  1. 1. P(A)=0.3P(A) = 0.3, P(B)=0.5P(B) = 0.5, P(AB)=0.15P(A \cap B) = 0.15. Are AA and BB independent?

    P(A)P(B)=0.15=P(AB)P(A) \cdot P(B) = 0.15 = P(A \cap B). Yes, independent.

    2. From the worked example, find P(femalepass)P(\text{female} | \text{pass}).

    P(Fpass)=P(Fpass)/P(pass)=0.48/0.760.632P(F|\text{pass}) = P(F \cap \text{pass})/P(\text{pass}) = 0.48/0.76 \approx 0.632.

    3. A card is drawn from a standard deck. What is P(red or face card)P(\text{red or face card})?

    P(red)=26/52P(\text{red}) = 26/52, P(face)=12/52P(\text{face}) = 12/52, P(red face)=6/52P(\text{red face}) = 6/52. P=(26+126)/52=32/52=8/13P = (26+12-6)/52 = 32/52 = 8/13.

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Summary

  • Addition rule: P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B).
  • Multiplication rule: P(AB)=P(A)P(BA)P(A \cap B) = P(A)P(B|A).
  • Independence: P(BA)=P(B)P(B|A) = P(B), equivalently P(AB)=P(A)P(B)P(A \cap B) = P(A)P(B).
  • Bayes' theorem reverses conditional probabilities.

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