Probability

AP Statistics guide to probability: basic rules, conditional probability, independence, Bayes' theorem, and counting principles.

# Probability — AP Statistics

Probability provides the mathematical framework for statistical inference. AP Statistics covers probability rules, conditional probability, independence, and the law of large numbers.

Key Concepts

Basic Probability

0≤P(A)≤10 \leq P(A) \leq 1 P(Ac)=1−P(A)P(A^c) = 1 - P(A)

Addition Rule

P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)

If AA and BB are mutually exclusive: P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B).

Multiplication Rule

P(A∩B)=P(A)⋅P(B∣A)P(A \cap B) = P(A) \cdot P(B|A)

If AA and BB are independent: P(A∩B)=P(A)⋅P(B)P(A \cap B) = P(A) \cdot P(B).

Conditional Probability

P(B∣A)=P(A∩B)P(A)P(B|A) = \frac{P(A \cap B)}{P(A)}

Independence

Events AA and BB are independent if P(B∣A)=P(B)P(B|A) = P(B).

Law of Large Numbers

As the number of trials increases, the sample proportion approaches the true probability.

Two-Way Tables

Use two-way tables to find joint, marginal, and conditional probabilities.

Tree Diagrams

Useful for visualizing sequential events and computing conditional probabilities (Bayes' theorem).

Bayes' Theorem

P(A∣B)=P(B∣A)⋅P(A)P(B)P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)}

Worked Example

Problem: In a class, 60% are female. Of females, 80% pass. Of males, 70% pass. Find P(pass)P(\text{pass}).

Solution: By the law of total probability: P(pass)=P(F)P(pass∣F)+P(M)P(pass∣M)P(\text{pass}) = P(F)P(\text{pass}|F) + P(M)P(\text{pass}|M) =0.6(0.8)+0.4(0.7)=0.48+0.28=0.76= 0.6(0.8) + 0.4(0.7) = 0.48 + 0.28 = 0.76

Practice Questions

  1. 1. P(A)=0.3P(A) = 0.3, P(B)=0.5P(B) = 0.5, P(A∩B)=0.15P(A \cap B) = 0.15. Are AA and BB independent?

    P(A)⋅P(B)=0.15=P(A∩B)P(A) \cdot P(B) = 0.15 = P(A \cap B). Yes, independent.

    2. From the worked example, find P(female∣pass)P(\text{female} | \text{pass}).

    P(F∣pass)=P(F∩pass)/P(pass)=0.48/0.76≈0.632P(F|\text{pass}) = P(F \cap \text{pass})/P(\text{pass}) = 0.48/0.76 \approx 0.632.

    3. A card is drawn from a standard deck. What is P(red or face card)P(\text{red or face card})?

    P(red)=26/52P(\text{red}) = 26/52, P(face)=12/52P(\text{face}) = 12/52, P(red face)=6/52P(\text{red face}) = 6/52. P=(26+12−6)/52=32/52=8/13P = (26+12-6)/52 = 32/52 = 8/13.

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Summary

  • Addition rule: P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B).
  • Multiplication rule: P(A∩B)=P(A)P(B∣A)P(A \cap B) = P(A)P(B|A).
  • Independence: P(B∣A)=P(B)P(B|A) = P(B), equivalently P(A∩B)=P(A)P(B)P(A \cap B) = P(A)P(B).
  • Bayes' theorem reverses conditional probabilities.

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