U-Substitution

Apply u-substitution for integration in AP Calculus AB. Handle both indefinite and definite integrals.

U-substitution reverses the chain rule for integration. It's the most important integration technique for AP Calculus AB.

Method

  1. Choose uu (the inner function).
  2. Find du=u′ dxdu = u'\,dx.
  3. Rewrite the integral in terms of uu.
  4. Integrate.
  5. Substitute back.

For Definite Integrals

Option A: Change the limits to uu-limits. Option B: Substitute back and use original limits.

Worked Example: Example 1

Problem

∫2x(x2+1)3 dx\int 2x(x^2+1)^3\,dx. Let u=x2+1u = x^2+1, du=2x dxdu = 2x\,dx. =∫u3 du=u44+C=(x2+1)44+C= \int u^3\,du = \frac{u^4}{4} + C = \frac{(x^2+1)^4}{4} + C.

Solution

Worked Example: Definite

Problem

∫01xex2 dx\int_0^1 xe^{x^2}\,dx. u=x2u = x^2, du=2x dxdu = 2x\,dx → x dx=du2x\,dx = \frac{du}{2}. Limits: x=0→u=0x=0 \to u=0, x=1→u=1x=1 \to u=1. =12∫01eu du=12(e−1)= \frac{1}{2}\int_0^1 e^u\,du = \frac{1}{2}(e-1).

Solution

Worked Example: Example 3

Problem

∫cos⁡xsin⁡x dx=∫duu=ln⁡∣u∣+C=ln⁡∣sin⁡x∣+C\int \frac{\cos x}{\sin x}\,dx = \int \frac{du}{u} = \ln|u| + C = \ln|\sin x| + C.

Solution

Practice Problems

    1. ∫(3x+1)5 dx\int (3x+1)^5\,dx.
    1. ∫exx dx\int \frac{e^{\sqrt{x}}}{\sqrt{x}}\,dx.
    1. ∫0π/2sin⁡3xcos⁡x dx\int_0^{\pi/2} \sin^3 x \cos x\,dx.

Want to check your answers and get step-by-step solutions?

Get it on Google PlayDownload on the App Store

Key Takeaways

  • ✓

    Choose uu so that dudu (or a constant multiple) appears.

  • ✓

    For definite integrals: change the limits or substitute back.

  • ✓

    U-sub reverses the chain rule.

Ready to Ace Your AP Calculus AB calculus?

Get instant step-by-step solutions to any problem. Snap a photo and learn with Tutor AI — your personal exam prep companion.

Get it on Google PlayDownload on the App Store