Percent Increase and Decrease

Welcome to one of the most high-yield topics on the Digital SAT. If you are aiming for a 700+ score, mastering **Percent Increase and Decrease** is non-neg

Welcome to one of the most high-yield topics on the Digital SAT. If you are aiming for a 700+ score, mastering Percent Increase and Decrease is non-negotiable. While percentages might seem like middle-school math, the SAT has a unique way of "wrapping" these concepts in wordy contexts, multi-step scenarios, and algebraic abstractions that can trip up even the strongest students.

In the Digital SAT Math section, you will encounter approximately 2 to 4 questions specifically targeting percent change within the Problem-Solving and Data Analysis domain. However, the influence of this topic extends much further. Percentages are the foundation for exponential growth and decay functions, interest rate problems, and data interpretation from tables and graphs. If you don't have a rock-solid grasp of how to manipulate percentage multipliers, you will struggle with some of the most difficult questions in Module 2.

The goal of this guide is to move you beyond the basic "percent over 100" formula. We are going to focus on the Multiplier Method. On the Digital SAT, speed and accuracy are everything. Using multipliers allows you to solve complex, multi-step problems in a single string of calculations on your Desmos calculator. By the end of this guide, you will be able to recognize percent change "keywords," set up equations for successive changes, and work backward from a final value to an initial value without breaking a sweat. We will transform percentages from a source of confusion into a source of easy points.

Core Concepts

To dominate this topic, you must move away from the "is over of" mentality and embrace the algebraic structure of percentage change.

1. The Percent Change Formula

The most fundamental way to calculate a percentage change between an old value and a new value is: Percent Change=(New ValueOld ValueOld Value)×100\text{Percent Change} = \left( \frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \right) \times 100

When to use it: Use this when the question asks, "By what percent did the value increase?" or "What was the percentage decrease?" SAT Trap: Students often divide by the New Value by mistake. Always remember: the "Old Value" (the original, starting, or reference point) is always the denominator.

2. The Multiplier Method (The 1±r1 \pm r Rule)

This is the most important tool in your SAT arsenal. Instead of calculating the "amount of change" and adding it back to the original, you should perform the calculation in one step.

If a value increases by r%r\%, the new value is: New=Original×(1+r)\text{New} = \text{Original} \times (1 + r) (Where rr is the percent written as a decimal.)

If a value decreases by r%r\%, the new value is: New=Original×(1r)\text{New} = \text{Original} \times (1 - r)

Examples:

  • An increase of 25%25\%: Multiply by (1+0.25)=1.25(1 + 0.25) = 1.25
  • A decrease of 15%15\%: Multiply by (10.15)=0.85(1 - 0.15) = 0.85
  • An increase of 110%110\%: Multiply by (1+1.10)=2.10(1 + 1.10) = 2.10
  • A decrease of 4%4\%: Multiply by (10.04)=0.96(1 - 0.04) = 0.96

3. Successive Percentage Changes

The SAT loves to apply multiple changes in a row. For example, a price might increase by 20%20\% and then decrease by 10%10\%. Crucial Rule: You cannot simply add or subtract the percentages (20%10%10%20\% - 10\% \neq 10\%). You must multiply the multipliers.

Final Value=Original×(1+r1)×(1r2)\text{Final Value} = \text{Original} \times (1 + r_1) \times (1 - r_2)

If a price PP increases by 20%20\% and then decreases by 10%10\%, the math is: Final=P×(1.20)×(0.90)=P×1.08\text{Final} = P \times (1.20) \times (0.90) = P \times 1.08 This shows the total change is actually an 8%8\% increase, not 10%10\%.

4. Working Backward (Finding the Original)

If the SAT gives you the "New Value" and the percentage change, and asks for the "Original Value," do NOT apply the percentage to the new value. Formula: Original=New Value1±r\text{Original} = \frac{\text{New Value}}{1 \pm r}

Example: A jacket costs \72afteraafter a20%$ discount. What was the original price? 72=Original×0.8072 = \text{Original} \times 0.80 Original=720.80=90\text{Original} = \frac{72}{0.80} = 90

5. Reference Sheet Note

Important: None of these formulas are on the SAT Math Reference Sheet. You must memorize the multiplier concept (1±r1 \pm r) and the percent change formula. The SAT expects you to internalize these as basic arithmetic tools.

SAT Strategy Tips

1. The "100" Trick

If a question asks for a percentage change but doesn't give you any actual numbers (only variables or percentages), pick 100 as your starting value. Example: "If the length of a rectangle increases by 20%20\% and the width decreases by 20%20\%, what is the change in area?"

  • Let L=10L = 10 and W=10W = 10 (Area = 100).
  • New L=12L = 12, New W=8W = 8.
  • New Area = 12×8=9612 \times 8 = 96.
  • Change from 100 to 96 is a 4%4\% decrease.

2. Translate English to Math

The SAT uses specific phrasing to hide the math. Learn to translate:

  • "What percent of xx is yy?" yx×100\rightarrow \frac{y}{x} \times 100
  • "xx is 30%30\% more than yy" x=1.30y\rightarrow x = 1.30y
  • "xx is 30%30\% less than yy" x=0.70y\rightarrow x = 0.70y
  • "The price was reduced by 20%20\%" New=0.80×Old\rightarrow \text{New} = 0.80 \times \text{Old}

3. Desmos is Your Best Friend

For successive changes, don't do them one by one. Type the entire string into the Desmos calculator. If a population of 500 grows by 12%12\% for 5 years, type 500(1.12)5500(1.12)^5. If a price of xx is taxed at 8%8\% and then discounted by 15%15\%, type x1.080.85x \cdot 1.08 \cdot 0.85.

4. Read the Final Question Carefully

The SAT often asks for something slightly different than what you just calculated. Does it ask for the new total, the amount of the increase, or the original value? A common trap is calculating the new price when the question asked "By how many dollars did the price increase?"

Worked Example: Medium

Problem

A tech company produced 1,2001,200 smartwatches in 2022. In 2023, the number of smartwatches produced increased by 15%15\%. In 2024, the production increased again by 10%10\% over the 2023 production level. How many smartwatches did the company produce in 2024?

Solution
  1. Identify the initial value: The starting production is 1,2001,200.
  2. Determine the first multiplier: An increase of 15%15\% means we multiply by (1+0.15)=1.15(1 + 0.15) = 1.15.
  3. Determine the second multiplier: An increase of 10%10\% means we multiply by (1+0.10)=1.10(1 + 0.10) = 1.10.
  4. Set up the equation: Production2024=1,200×1.15×1.10\text{Production}_{2024} = 1,200 \times 1.15 \times 1.10
  5. Calculate: 1,200×1.15=1,3801,200 \times 1.15 = 1,380 1,380×1.10=1,5181,380 \times 1.10 = 1,518 Final Answer: 1,5181,518

Worked Example: Hard

Problem

The price of a laptop was discounted by 20%20\% during a holiday sale. After the sale ended, the discounted price was increased by 25%25\% to return it to a "new" retail price. What is the relationship between the original price and the new retail price?

Solution
  1. Pick a starting number: Let the original price be \100$.
  2. Apply the discount: A 20%20\% discount means the multiplier is 0.800.80. 100×0.80=80100 \times 0.80 = 80
  3. Apply the increase: A 25%25\% increase on the sale price means the multiplier is 1.251.25. 80×1.25=10080 \times 1.25 = 100
  4. Compare: The original price was \100andthenewretailpriceisand the new retail price is$100.FinalAnswer:Thenewretailpriceisequaltotheoriginalprice.(Note:Manystudentsassumeitwouldbehigherorlowerbecause. **Final Answer:** The new retail price is equal to the original price. (Note: Many students assume it would be higher or lower because 25%is"bigger"thanis "bigger" than20%$, but the math proves they cancel out.)

Worked Example: SAT-Hard

Problem

In a certain forest, the population of deer increased by x%x\% from 2010 to 2015, and then decreased by 20%20\% from 2015 to 2020. If the population in 2020 was 4%4\% greater than the population in 2010, what is the value of xx?

Solution
  1. Define variables: Let PP be the population in 2010.
  2. Set up the multipliers:
    • Increase of x%x\%: Multiplier is (1+x100)(1 + \frac{x}{100})
    • Decrease of 20%20\%: Multiplier is 0.800.80
  3. Express the final population: The final population is 4%4\% greater than PP, so it is 1.04P1.04P.
  4. Create the equation: P×(1+x100)×0.80=1.04PP \times (1 + \frac{x}{100}) \times 0.80 = 1.04P
  5. Solve for xx: Divide both sides by PP: (1+x100)×0.80=1.04(1 + \frac{x}{100}) \times 0.80 = 1.04 Divide by 0.800.80: 1+x100=1.040.801 + \frac{x}{100} = \frac{1.04}{0.80} 1+x100=1.31 + \frac{x}{100} = 1.3 Subtract 1: x100=0.3\frac{x}{100} = 0.3 x=30x = 30 Final Answer: 3030

Practice Problems

  1. A vintage camera was purchased for \450.Twoyearslater,itsvaluehadincreasedby. Two years later, its value had increased by 12%.Afteranotheryear,thevaluedecreasedby. After another year, the value decreased by 5%$ from its two-year value. To the nearest dollar, what is the current value of the camera?

  2. The number of students in a coding club increased by 20%20\% from last year to this year. If there are 7272 students in the club this year, how many students were in the club last year?

  3. A store manager increases the price of an item by p%p\%. Later, she reduces this new price by p%p\%. If the final price is 91%91\% of the original price, what is the value of pp?

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Common Mistakes

1. Adding Percentages

The Mistake: If a stock goes up 10%10\% on Monday and down 10%10\% on Tuesday, students think it’s back to the original price. Why it’s wrong: The second percentage is applied to a new, larger number. How to avoid: Always use multipliers. 1.10×0.90=0.991.10 \times 0.90 = 0.99. The stock is actually down 1%1\%.

2. Using the Wrong Base (Denominator)

The Mistake: When asked for the percent change from 8080 to 100100, a student calculates 10080100=20%\frac{100-80}{100} = 20\%. Why it’s wrong: The "original" value is 8080, not 100100. How to avoid: Always put the "starting" value in the denominator. 2080=25%\frac{20}{80} = 25\%.

3. Forgetting the "1" in the Multiplier

The Mistake: To find a 5%5\% increase of 200200, a student multiplies 200×0.05200 \times 0.05 and gets 1010. Why it’s wrong: 1010 is the amount of the increase, not the new total. How to avoid: If the question asks for the new total, use (1+r)(1 + r). 200×1.05=210200 \times 1.05 = 210.

4. Applying Percentages to the Wrong Value

The Mistake: If a price after a 10%10\% tax is \110,studentscalculate, students calculate 10%ofof$110( ($11)andsubtractittofindtheoriginalprice() and subtract it to find the original price ($99).Whyitswrong:Thetaxwas). **Why it’s wrong:** The tax was 10%oftheoriginalprice,notthefinalprice.Howtoavoid:Setupanequation:of the *original* price, not the final price. **How to avoid:** Set up an equation:1.10x = 110,so, so x = 100$.

Frequently Asked Questions

Can I use the Desmos calculator for all percentage questions?

A: Absolutely. In fact, you should. Desmos is excellent for handling long chains of multipliers and for solving equations where the variable is part of a percentage (like Example 3).

How do I know if I should use $(1+r)$ or just $r$?

A: Read the verb. If the question asks for the "total," "result," or "new value," use (1+r)(1+r). If it asks for the "amount of increase," "interest earned," or "discount amount," use just rr.

How does this topic connect to Exponential Growth?

A: Exponential growth is just percent increase applied repeatedly over time. The formula A=P(1+r)tA = P(1+r)^t is exactly the same as our multiplier method, where (1+r)(1+r) is the multiplier and tt is how many times you apply it.

Key Takeaways

  • The Multiplier is King: Always convert percent changes to 1+r1+r or 1r1-r.

  • Successive Changes Multiply: Never add percentages together; multiply their corresponding multipliers.

  • Original = Denominator: When calculating percent change, always divide by the starting value.

  • Work Backward with Division: To find the original value, divide the final value by the multiplier.

  • Pick 100: If no starting number is given, use 100 to make the math intuitive.

  • Read Carefully: Distinguish between the "amount of change" and the "new total."

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