Mean, Median, and Mode

Welcome to one of the most high-yield topics in the Digital SAT Math section: **Measures of Center**. While you likely learned about mean, median, and mode

Welcome to one of the most high-yield topics in the Digital SAT Math section: Measures of Center. While you likely learned about mean, median, and mode in middle school, the SAT takes these foundational concepts and applies them in sophisticated, data-driven contexts. On the Digital SAT, you can expect to see approximately 2 to 4 questions per test specifically targeting these skills within the Problem-Solving and Data Analysis domain.

Why does the SAT care so much about averages? In the real world, data is messy. Scientists, business analysts, and policymakers use measures of center to summarize vast amounts of information. The SAT isn't just testing if you can add numbers and divide; it’s testing if you understand the story the data is telling. You will be asked to calculate these values from lists, frequency tables, and dot plots, and—more importantly—you will be asked to predict how these values change when the data set is altered.

In this guide, we are going to move beyond the basic definitions. We will master the "Sum Formula" (the secret weapon for mean questions), learn how to navigate frequency tables without getting lost, and understand the conceptual relationship between the mean and median when outliers are present. By the end of this module, you won't just be "doing math"—you'll be analyzing data like a pro. These are "must-get" points that separate the 600-level scorers from the 700+ elite. Let's dive in.


Core Concepts

To master this section, you must be comfortable with three primary measures of center and the specific ways the SAT presents them.

1. The Arithmetic Mean

The mean is the "average" you are most familiar with. It is calculated by summing all the values in a data set and dividing by the total number of values.

The Formula: Mean(xˉ)=xn=Sum of valuesNumber of values\text{Mean} (\bar{x}) = \frac{\sum x}{n} = \frac{\text{Sum of values}}{\text{Number of values}}

The SAT "Sum" Trick: Most students focus on the mean itself, but the SAT often gives you the mean and asks for a missing value. In these cases, the Sum Formula is much more useful: Sum=Mean×Number of values\text{Sum} = \text{Mean} \times \text{Number of values} If you know the average of 5 tests is 90, you immediately know the total points earned is 90×5=45090 \times 5 = 450. This is the most common "move" on mean-related word problems.

2. The Median

The median is the middle value of a data set when the numbers are arranged in ascending or descending order.

  • If nn is odd: The median is the exact middle number. Its position can be found using n+12\frac{n+1}{2}.
  • If nn is even: The median is the average of the two middle numbers.

When it appears: The SAT loves to ask for the median from a frequency table or dot plot. You must be careful not to pick the middle number in the "frequency" column, but rather the value that corresponds to the middle position of the total count.

3. The Mode

The mode is the value that appears most frequently in a data set. A set can have one mode, more than one mode (bimodal/multimodal), or no mode at all. On the SAT, mode is usually the simplest concept tested, often appearing in questions asking you to identify the most common response in a survey.

4. Weighted Averages

A weighted average occurs when different groups contribute differently to the final mean. For example, if Class A has 10 students with an average of 80 and Class B has 20 students with an average of 90, the total average is NOT 85.

The Formula: Weighted Mean=(n1×xˉ1)+(n2×xˉ2)n1+n2\text{Weighted Mean} = \frac{(n_1 \times \bar{x}_1) + (n_2 \times \bar{x}_2)}{n_1 + n_2} In our example: (10×80)+(20×90)10+20=800+18003086.7\frac{(10 \times 80) + (20 \times 90)}{10 + 20} = \frac{800 + 1800}{30} \approx 86.7.

5. Mean vs. Median (Shape of Data)

The SAT frequently asks how an outlier (a value much higher or lower than the rest) affects the mean and median.

  • Mean: Highly sensitive to outliers. A very high value will pull the mean up; a very low value will pull it down.
  • Median: Resistant to outliers. Because it only cares about the middle position, an extreme value at the end of the list rarely changes the median significantly.

Important Note: None of these formulas are provided on the SAT Reference Sheet. You must memorize them and, more importantly, understand how to manipulate them.


SAT Strategy Tips

1. Use the Desmos Calculator

The Digital SAT includes an integrated Desmos calculator. For any question providing a list of numbers, use the mean() and median() functions.

  • Type L = [1, 2, 3, 4, 5] to create a list.
  • Type mean(L) or median(L) to get instant results. This eliminates calculation errors and saves precious seconds.

2. The "Balance" Concept

Think of the mean as the balance point of a seesaw. If you add a number greater than the current mean, the mean must increase. If you add a number smaller than the mean, the mean must decrease. If you add a number exactly equal to the mean, the mean stays the same. This conceptual understanding often allows you to solve "impact" questions without doing any math.

3. Frequency Table Navigation

When given a frequency table, always calculate the cumulative frequency to find the median. If there are 51 total items, the median is the 26th26^{th} item (51+12=26\frac{51+1}{2} = 26). Count through the frequencies until you hit the 26th26^{th} value.

4. Watch for "Must be True" vs. "Could be True"

Data analysis questions often use this phrasing. If a question asks what must be true about the median when a value is added, test the most extreme scenarios. If the conclusion holds in all cases, it's the correct answer.


Worked Example: The Missing Value (Medium

Problem

A student has taken 4 exams and earned scores of 82, 88, 91, and 83. What score must the student earn on the 5th5^{th} exam to have an overall mean score of 87?

Solution
  1. Identify the goal: We need the mean of 5 exams to be 87.
  2. Use the Sum Formula: Total Sum=Mean×n\text{Total Sum} = \text{Mean} \times n. Total Sum=87×5=435\text{Total Sum} = 87 \times 5 = 435
  3. Sum the known scores: 82+88+91+83=34482 + 88 + 91 + 83 = 344
  4. Find the difference: The 5th5^{th} score (xx) must make up the difference between the current sum and the required sum. 344+x=435344 + x = 435 x=435344=91x = 435 - 344 = 91 Final Answer: 91

Worked Example: Median from Frequency (Hard

Problem

The table below shows the distribution of the number of books read by 25 students over the summer. What is the median number of books read?

Books Read Number of Students (Frequency)
0 4
1 8
2 7
3 3
4 3
Solution
  1. Find the total number of data points (nn): The problem states there are 25 students.
  2. Determine the median position: Since 25 is odd, the median is at position 25+12=13\frac{25+1}{2} = 13. We are looking for the 13th13^{th} value.
  3. Track cumulative frequency:
    • Students who read 0 books: Positions 1–4.
    • Students who read 1 book: Positions 5–12 (since 4+8=124 + 8 = 12).
    • Students who read 2 books: Positions 13–19 (since 12+7=1912 + 7 = 19).
  4. Identify the value at the 13th13^{th} position: The 13th13^{th} student falls into the "2 books" category. Final Answer: 2

Worked Example: Impact of Outliers (SAT-Hard

Problem

A data set consists of 10 positive integers: {10,12,12,14,15,15,15,17,18,20}\{10, 12, 12, 14, 15, 15, 15, 17, 18, 20\}. A new value, 60, is added to the data set to create a new set of 11 integers. Which of the following statements correctly describes the change in the mean and median?

A) The mean increases more than the median. B) The median increases more than the mean. C) The mean and median increase by the same amount. D) The mean increases, but the median decreases.

Solution
  1. Analyze the original set:
    • Original Mean: 10+12+12+14+15+15+15+17+18+2010=14810=14.8\frac{10+12+12+14+15+15+15+17+18+20}{10} = \frac{148}{10} = 14.8.
    • Original Median: The average of the 5th5^{th} and 6th6^{th} values (15 and 15) is 15.
  2. Analyze the new set (adding 60):
    • New Mean: 148+6011=2081118.9\frac{148 + 60}{11} = \frac{208}{11} \approx 18.9.
    • New Median: The 6th6^{th} value in the sorted list of 11. The list is now {10,12,12,14,15,15,15,17,18,20,60}\{10, 12, 12, 14, 15, 15, 15, 17, 18, 20, 60\}. The 6th6^{th} value is 15.
  3. Compare the changes:
    • Mean change: 18.914.8=4.118.9 - 14.8 = 4.1 (Increase).
    • Median change: 1515=015 - 15 = 0 (No change).
  4. Conclusion: The mean increased significantly because 60 is an outlier, while the median remained unchanged. Final Answer: A

Practice Problems

  1. A set of 7 numbers has a mean of 12. If a new number, kk, is added to the set, the new mean of the 8 numbers is 15. What is the value of kk?

  2. The dot plot below represents the number of hours 15 employees spent on a project. If an 16th employee, who spent 10 hours on the project, is added to the data, which measure of center will change the most: the mean, the median, or the mode? (Imagine a dot plot where most values are between 1 and 4, and one value is at 10).

  3. In a survey of 40 households, the number of pets per household was recorded. The results showed a mean of 1.5 pets and a median of 1 pet. If 5 more households are surveyed and each has exactly 2 pets, will the new mean be greater than, less than, or equal to the original mean?


Want to check your answers and get step-by-step solutions?

Get it on Google PlayDownload on the App Store

Common Mistakes

1. Forgetting to Order the Data

This is the #1 mistake on median questions. Students often look at a list like {5,2,8,1,9}\{5, 2, 8, 1, 9\} and pick "8" because it's in the middle of the written list. You must rewrite it as {1,2,5,8,9}\{1, 2, 5, 8, 9\} to find the median (5).

  • How to avoid: Always use the Desmos median() function or check off numbers as you re-list them.

2. Confusing Frequency with the Data Value

In a table, students often calculate the mean of the "Frequency" column instead of the "Value" column.

  • Why it's wrong: The frequency is just a count of how many times a value appears.
  • How to avoid: Remember that the "Sum" in the mean formula is (Value×Frequency)\sum (\text{Value} \times \text{Frequency}).

3. Miscalculating the Median Position in Even Sets

If n=20n=20, the median is NOT the 10th10^{th} value. It is the average of the 10th10^{th} and 11th11^{th} values.

  • How to avoid: Use the formula n2\frac{n}{2} and n2+1\frac{n}{2} + 1 to find the two middle positions for even sets.

Frequently Asked Questions

Do I need to know Standard Deviation for these questions?

A: While Standard Deviation is a "measure of spread" (not center), it often appears alongside mean/median questions. You don't need to calculate it (the formula is too complex for the SAT), but you do need to know that a "higher standard deviation" means the data is more spread out from the mean.

Can I just use Desmos for every mean and median question?

A: Almost! Desmos is perfect for lists. However, for frequency tables with large numbers (e.g., a value of 10 appearing 500 times), you can't type them all out. You'll need to use the weighted average logic or the cumulative frequency method described above.

How does this connect to "Range"?

A: Range is the difference between the maximum and minimum values. The SAT often asks how adding an outlier affects the mean, median, and range. While the mean and range will change drastically with an outlier, the median usually stays stable.


Key Takeaways

  • The Sum Formula: Sum=Mean×n\text{Sum} = \text{Mean} \times n. Use this for almost every "missing value" mean problem.

  • Median = Position: The median is the value at the middle position, not the middle of the frequencies.

  • Outlier Impact: Outliers pull the mean toward them but usually leave the median alone.

  • Frequency Tables: To find the mean, multiply each value by its frequency, sum them up, and divide by the total frequency.

  • Desmos is your friend: Use mean([list]) and median([list]) to ensure 100% accuracy on simple data sets.

  • Order Matters: Never calculate a median without ensuring the data is in order from least to greatest.

Ready to Ace Your SAT math?

Get instant step-by-step solutions to any problem. Snap a photo and learn with Tutor AI — your personal exam prep companion.

Get it on Google PlayDownload on the App Store