Direct and Inverse Variation

Understand direct and inverse variation for the Digital SAT. Recognise y = kx and y = k/x patterns from tables, graphs, and word problems.

Direct and inverse variation describe two fundamental relationships between variables. In direct variation, as one increases, the other increases proportionally. In inverse variation, as one increases, the other decreases proportionally. The Digital SAT tests both, often through tables, graphs, or word problems.

Core Concepts

Direct Variation

y=kxy = kx

where kk is the constant of variation (or constant of proportionality).

  • As xx increases, yy increases.
  • The ratio yx=k\frac{y}{x} = k is constant.
  • The graph passes through the origin.

Example: If yy varies directly with xx and y=15y = 15 when x=3x = 3, find kk and the equation.

k=153=5k = \frac{15}{3} = 5. Equation: y=5xy = 5x.

Inverse Variation

y=kxor equivalentlyxy=ky = \frac{k}{x} \quad \text{or equivalently} \quad xy = k

where kk is the constant of variation.

  • As xx increases, yy decreases.
  • The product xy=kxy = k is constant.
  • The graph is a hyperbola.

Example: If yy varies inversely with xx and y=6y = 6 when x=4x = 4, find kk.

k=xy=24k = xy = 24. Equation: y=24xy = \frac{24}{x}.

Identifying from Tables

Direct: Check if yx\frac{y}{x} is constant.

xx yy y/xy/x
2 8 4
5 20 4
7 28 4

Direct variation with k=4k = 4.

Inverse: Check if xyxy is constant.

xx yy xyxy
2 12 24
3 8 24
6 4 24

Inverse variation with k=24k = 24.

Identifying from Graphs

  • Direct variation: straight line through the origin.
  • Inverse variation: hyperbola (curve approaching the axes).

Strategy Tips

Tip 1: Find kk First

Use a given pair (x,y)(x, y) to find kk, then use kk to answer the question.

Tip 2: "Proportional" = Direct Variation

"yy is proportional to xx" means y=kxy = kx.

Tip 3: "Inversely Proportional" = Inverse Variation

"yy is inversely proportional to xx" means y=k/xy = k/x.

Tip 4: Check Both Patterns

If given a table and asked about the relationship, compute both y/xy/x and xyxy to see which is constant.

Worked Example: Example 1

Problem

yy varies directly with xx. If y=12y = 12 when x=4x = 4, find yy when x=7x = 7.

k=12/4=3k = 12/4 = 3. y=3(7)=21y = 3(7) = 21.

Solution

Worked Example: Example 2

Problem

yy varies inversely with xx. If y=10y = 10 when x=3x = 3, find yy when x=5x = 5.

k=30k = 30. y=30/5=6y = 30/5 = 6.

Solution

Worked Example: SAT-Style

Problem

The number of workers and the time to complete a job are inversely proportional. If 6 workers complete the job in 10 hours, how long does it take 15 workers?

k=6×10=60k = 6 \times 10 = 60. Time =60/15=4= 60/15 = 4 hours.

Solution

Worked Example: Example 4

Problem

Is the relationship in the table direct, inverse, or neither?

xx yy
1 5
2 7
3 9

y/xy/x: 5, 3.5, 3 — not constant. xyxy: 5, 14, 27 — not constant. Neither (it's linear but not proportional: y=2x+3y = 2x + 3).

Solution

Practice Problems

  1. Problem 1

    y=kxy = kx. If y=20y = 20 when x=8x = 8, find yy when x=12x = 12.

    Problem 2

    yy varies inversely with xx. If y=4y = 4 when x=9x = 9, find xx when y=6y = 6.

    Problem 3

    Speed and time for a fixed distance: direct or inverse variation?

    Problem 4

    A table: xx = 3, 6, 9; yy = 18, 9, 6. Direct or inverse?

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Common Mistakes

  • Confusing direct and inverse. Direct: yy increases as xx increases. Inverse: yy decreases as xx increases.
  • Thinking all linear relationships are direct variation. Only y=kxy = kx (through the origin) is direct variation. y=kx+by = kx + b with b0b \neq 0 is not.
  • Using the wrong formula. Direct: y=kxy = kx. Inverse: y=k/xy = k/x.

Key Takeaways

  • Direct variation: y=kxy = kx, y/x=ky/x = k is constant, graph through origin.

  • Inverse variation: y=k/xy = k/x, xy=kxy = k is constant, hyperbola graph.

  • Find kk from a given pair, then use to find unknowns.

  • "Proportional" = direct. "Inversely proportional" = inverse.

  • Not every linear relationship is direct variation — it must pass through the origin.

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