Central Angles, Inscribed Angles, and Tangent Lines

Master circle angle theorems for the Digital SAT. Understand inscribed angles, central angles, and tangent-radius relationships.

Circle theorems connect angles, arcs, and lines in powerful ways. The Digital SAT tests central angles, inscribed angles, and tangent line properties. These appear in both pure geometry problems and coordinate geometry contexts.

Core Concepts

Central Angle

A central angle has its vertex at the centre of the circle. Its measure equals the intercepted arc.

Central angle=intercepted arc\text{Central angle} = \text{intercepted arc}

Inscribed Angle

An inscribed angle has its vertex on the circle. Its measure is half the intercepted arc.

Inscribed angle=12×intercepted arc\text{Inscribed angle} = \frac{1}{2} \times \text{intercepted arc}

Inscribed Angle Theorem

An inscribed angle is half the central angle that subtends the same arc:

Inscribed angle=12×central angle\text{Inscribed angle} = \frac{1}{2} \times \text{central angle}

Angle in a Semicircle

An inscribed angle that subtends a diameter is always 90°.

Tangent Line Properties

  • A tangent line touches the circle at exactly one point.
  • A tangent is perpendicular to the radius at the point of tangency.
  • Two tangent segments from the same external point are equal in length.

Tangent-Radius Right Angle

If a line is tangent to a circle at point PP, and OO is the centre, then OPT=90°\angle OPT = 90° (where TT is along the tangent).

Strategy Tips

Tip 1: Draw the Radius to the Tangent Point

This creates a right angle, which often enables Pythagorean theorem or trig.

Tip 2: Inscribed = Half Central

This is the most-tested relationship.

Tip 3: Diameter → 90° Inscribed Angle

If the inscribed angle sits on a diameter, it's automatically 90°.

Worked Example: Example 1

Problem

Central angle = 120°. What is the inscribed angle subtending the same arc?

Inscribed angle = 120/2=60°120/2 = 60°.

Solution

Worked Example: Example 2

Problem

An inscribed angle is 35°. What is the intercepted arc?

Arc = 35×2=70°35 \times 2 = 70°.

Solution

Worked Example: SAT-Style

Problem

A tangent from point PP touches a circle of radius 5 at point TT. If PT=12PT = 12, find the distance from PP to the centre OO.

OTPTOT \perp PT, so use Pythagorean theorem: PO=122+52=169=13PO = \sqrt{12^2 + 5^2} = \sqrt{169} = 13.

Solution

Worked Example: Example 4

Problem

Triangle ABCABC is inscribed in a circle with BCBC as a diameter. What is BAC\angle BAC?

Angle in a semicircle = 90°90°.

Solution

Worked Example: Example 5

Problem

Two tangent lines from external point PP touch the circle at AA and BB. If PA=8PA = 8, what is PBPB?

PB=PA=8PB = PA = 8 (tangent segments from same point are equal).

Solution

Practice Problems

  1. Problem 1

    Central angle 80°. Find the inscribed angle for the same arc.

    Problem 2

    Inscribed angle 55°. Find the intercepted arc.

    Problem 3

    Tangent from PP, PT=15PT = 15, radius = 8. Find POPO.

    Problem 4

    A triangle inscribed in a circle has one side as a diameter and another angle of 30°. Find all angles.

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Common Mistakes

  • Doubling when you should halve (or vice versa). Inscribed = HALF the central angle.
  • Forgetting the tangent-radius right angle. This is essential for solving tangent problems.
  • Confusing central and inscribed angles. Central angle vertex is at the centre; inscribed angle vertex is on the circle.

Key Takeaways

  • Inscribed angle = ½ central angle for the same arc.

  • Angle in a semicircle = 90°.

  • Tangent ⊥ radius at the point of tangency.

  • Equal tangent segments from the same external point.

  • Draw radii and tangent lines to create right triangles for problem-solving.

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