Arc Length and Sector Area

Calculate arc length and sector area for the Digital SAT using the fraction-of-a-circle method.

An arc is a portion of a circle's circumference, and a sector is a "pizza slice" portion of a circle's area. Both are calculated as a fraction of the full circle. The Digital SAT tests these calculations in both degree and radian contexts.

Core Concepts

Fraction of the Circle

A central angle θ\theta out of 360°360° gives the fraction:

fraction=θ360°\text{fraction} = \frac{\theta}{360°}

Arc Length

Arc length=θ360°×2πr\text{Arc length} = \frac{\theta}{360°} \times 2\pi r

In radians: Arc length=rθ\text{Arc length} = r\theta

Sector Area

Sector area=θ360°×πr2\text{Sector area} = \frac{\theta}{360°} \times \pi r^2

In radians: Sector area=12r2θ\text{Sector area} = \frac{1}{2}r^2\theta

Relationship

Arc length and sector area use the same fraction of the circle, applied to circumference and area respectively.

Strategy Tips

Tip 1: Find the Fraction First

Always start by computing θ360\frac{\theta}{360} (or θ2π\frac{\theta}{2\pi} in radians).

Tip 2: Radian Formulas Are Simpler

In radians, arc length =rθ= r\theta and sector area =12r2θ= \frac{1}{2}r^2\theta.

Tip 3: Check Degree vs. Radian

Make sure your angle is in the same units as your formula expects.

Worked Example: Example 1

Problem

Circle radius 10, central angle 72°. Find arc length.

Fraction: 72360=15\frac{72}{360} = \frac{1}{5}

Arc = 15×2π(10)=4π12.57\frac{1}{5} \times 2\pi(10) = 4\pi \approx 12.57

Solution

Worked Example: Example 2

Problem

Circle radius 6, central angle π3\frac{\pi}{3}. Find sector area.

A=12(6)2(π3)=12(36)(π3)=6π18.85A = \frac{1}{2}(6)^2\left(\frac{\pi}{3}\right) = \frac{1}{2}(36)\left(\frac{\pi}{3}\right) = 6\pi \approx 18.85

Solution

Worked Example: SAT-Style

Problem

A pizza with diameter 16 inches is cut into 8 equal slices. What is the area of one slice?

r=8r = 8. Angle per slice = 3608=45°\frac{360}{8} = 45°.

A=45360×π(8)2=18×64π=8π25.1A = \frac{45}{360} \times \pi(8)^2 = \frac{1}{8} \times 64\pi = 8\pi \approx 25.1 sq in.

Solution

Worked Example: Example 4

Problem

Arc length is 5π and radius is 10. Find the central angle in degrees.

5π=θ360×2π(10)5\pi = \frac{\theta}{360} \times 2\pi(10)

5π=20πθ3605\pi = \frac{20\pi\theta}{360}

θ=5×36020=90°\theta = \frac{5 \times 360}{20} = 90°

Solution

Practice Problems

  1. Problem 1

    Radius 12, angle 120°. Find arc length.

    Problem 2

    Radius 5, angle π4\frac{\pi}{4}. Find sector area.

    Problem 3

    A sector has area 24π24\pi and radius 88. Find the central angle.

    Problem 4

    A circular track has radius 50 m. How far do you travel through a 60° turn?

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Common Mistakes

  • Using diameter instead of radius.
  • Mixing up degrees and radians in the formula.
  • Forgetting to use the fraction. The full circumference is 2πr2\pi r; the arc is a fraction of it.
  • Computing arc length when sector area is asked (or vice versa).

Key Takeaways

  • Fraction of circle: θ360°\frac{\theta}{360°} (degrees) or θ2π\frac{\theta}{2\pi} (radians).

  • Arc length = fraction × circumference. In radians: rθr\theta.

  • Sector area = fraction × area. In radians: 12r2θ\frac{1}{2}r^2\theta.

  • Always check degree vs. radian mode.

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