Angle Relationships and Parallel Lines

Master angle relationships with parallel lines and transversals for the Digital SAT. Identify corresponding, alternate, and co-interior angles.

When a line (transversal) crosses two parallel lines, it creates pairs of angles with special relationships. The Digital SAT tests your ability to identify these relationships and use them to find unknown angles.

Core Concepts

Vertical Angles

When two lines cross, opposite angles are equal: a=ca = c and b=db = d.

Also: a+b=180°a + b = 180° (supplementary).

Parallel Lines and Transversals

When a transversal crosses parallel lines:

Corresponding angles (same position): equal.

Alternate interior angles (opposite sides, between parallels): equal.

Alternate exterior angles (opposite sides, outside parallels): equal.

Co-interior (same-side interior) angles (same side, between parallels): supplementary (sum to 180°).

Angle Sum Rules

  • Angles on a straight line sum to 180°180°.
  • Angles at a point sum to 360°360°.
  • Interior angles of a triangle sum to 180°180°.

Strategy Tips

Tip 1: Label the Parallel Lines

Mark parallel lines with arrows. Identify the transversal.

Tip 2: Look for Z, F, and C Shapes

  • Z-shape: alternate angles (equal).
  • F-shape: corresponding angles (equal).
  • C-shape (or U-shape): co-interior angles (sum to 180°).

Tip 3: Use Multiple Steps

You may need to find one angle using vertical angles, then use that to find another via parallel line relationships.

Worked Example: Example 1

Problem

Lines ll and mm are parallel. A transversal makes a 65° angle with line ll. Find the alternate interior angle at line mm.

Alternate interior angles are equal: 65°.

Solution

Worked Example: Example 2

Problem

A transversal crosses two parallel lines. One angle is 110°. Find all eight angles.

The eight angles come in two groups: 110° and 70° (since 180°110°=70°180° - 110° = 70°). Corresponding/alternate angles are equal; supplementary pairs sum to 180°.

Solution

Worked Example: SAT-Style

Problem

In the figure, lines pp and qq are parallel. If angle 1 = 3x+103x + 10 and angle 2 = 5x305x - 30 (where they are alternate interior angles), find xx.

3x+10=5x303x + 10 = 5x - 3040=2x40 = 2xx=20x = 20

Angle = 3(20)+10=70°3(20) + 10 = 70°.

Solution

Worked Example: Example 4

Problem

Co-interior angles: one is 2x+152x + 15 and the other is 3x+253x + 25. Find xx.

(2x+15)+(3x+25)=180(2x + 15) + (3x + 25) = 1805x+40=1805x + 40 = 1805x=1405x = 140x=28x = 28

Solution

Practice Problems

  1. Problem 1

    Two parallel lines cut by a transversal. One angle is 55°. Find the co-interior angle.

    Problem 2

    Corresponding angles: one is 4x104x - 10 and the other is 2x+302x + 30. Find xx.

    Problem 3

    Find all angles when a transversal makes a 72° angle with one of two parallel lines.

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Common Mistakes

  • Confusing alternate and co-interior angles. Alternate = equal. Co-interior = supplementary.
  • Forgetting that lines must be parallel for these rules to apply.
  • Misidentifying which angles are corresponding. They must be in the same relative position.

Key Takeaways

  • Corresponding angles: equal (F-shape).

  • Alternate interior angles: equal (Z-shape).

  • Co-interior angles: supplementary, sum to 180° (C-shape).

  • Vertical angles: always equal.

  • These rules only apply when lines are parallel.

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