Parallel and Perpendicular Lines

Master parallel and perpendicular line relationships for the Digital SAT. Understand slope conditions and write equations of related lines.

Parallel and perpendicular lines have special slope relationships that the Digital SAT tests regularly. If you know the slope of one line, you can instantly determine the slope of any line parallel or perpendicular to it. This topic combines slope concepts with equation-writing skills and appears in both the algebra and geometry sections of the SAT.

Core Concepts

Parallel Lines

Two lines are parallel if they have the same slope but different y-intercepts.

m1=m2(parallel)m_1 = m_2 \quad \text{(parallel)}

Parallel lines never intersect. In a system of equations, parallel lines mean no solution.

Example: y=3x+5y = 3x + 5 is parallel to y=3x2y = 3x - 2 (both have slope 3).

Perpendicular Lines

Two lines are perpendicular if their slopes are negative reciprocals of each other.

m1×m2=1(perpendicular)m_1 \times m_2 = -1 \quad \text{(perpendicular)}

Equivalently: m2=1m1m_2 = -\frac{1}{m_1}

Perpendicular lines meet at a 90° angle.

Example: If a line has slope 23\frac{2}{3}, a perpendicular line has slope 32-\frac{3}{2}.

Example: If a line has slope 4-4, a perpendicular line has slope 14\frac{1}{4}.

Finding Slope from Any Equation Form

  • Slope-intercept y=mx+by = mx + b: slope is mm
  • Standard form Ax+By=CAx + By = C: slope is AB-\frac{A}{B}
  • Point-slope yy1=m(xx1)y - y_1 = m(x - x_1): slope is mm

Writing Equations of Parallel Lines

To write the equation of a line parallel to a given line and passing through a specific point:

  1. Find the slope of the given line.
  2. Use the same slope (parallel = same slope).
  3. Use point-slope form with the given point.

Example: Write the equation of the line parallel to y=2x+5y = 2x + 5 passing through (3,1)(3, 1).

Slope: m=2m = 2

y1=2(x3)y - 1 = 2(x - 3) y=2x5y = 2x - 5

Writing Equations of Perpendicular Lines

  1. Find the slope of the given line.
  2. Take the negative reciprocal for the perpendicular slope.
  3. Use point-slope form with the given point.

Example: Write the equation of the line perpendicular to y=13x+4y = -\frac{1}{3}x + 4 passing through (2,7)(2, 7).

Original slope: 13-\frac{1}{3} → Perpendicular slope: 33

y7=3(x2)y - 7 = 3(x - 2) y=3x+1y = 3x + 1

Special Cases

  • A horizontal line (y=ky = k, slope =0= 0) is perpendicular to a vertical line (x=kx = k, slope undefined).
  • Two horizontal lines are parallel to each other.
  • Two vertical lines are parallel to each other.

Strategy Tips

Tip 1: Negative Reciprocal Drill

Practise finding negative reciprocals instantly:

Original slope Negative reciprocal
22 12-\frac{1}{2}
3-3 13\frac{1}{3}
45\frac{4}{5} 54-\frac{5}{4}
17-\frac{1}{7} 77
11 1-1

Tip 2: Quick Check — Multiply the Slopes

To verify perpendicularity, multiply the two slopes. If the product is 1-1, they're perpendicular.

Tip 3: Convert to Slope-Intercept First

If the equation is in standard form, convert to y=mx+by = mx + b to easily identify the slope.

Tip 4: Don't Confuse Parallel with Perpendicular

Parallel = same slope. Perpendicular = negative reciprocal. The SAT sometimes tries to trick you by mixing these up in answer choices.

Tip 5: Look at the Graph

If a graph is provided, visually check: do the lines appear to meet at a right angle? Do they appear to never meet? Use this to guide your algebraic work.

Worked Example: Example 1

Problem

Line ll has equation 3x+6y=183x + 6y = 18. What is the slope of a line parallel to ll?

Convert: 6y=3x+186y = -3x + 18y=12x+3y = -\frac{1}{2}x + 3

Slope =12= -\frac{1}{2}

Parallel slope =12= -\frac{1}{2}

Solution

Worked Example: Example 2

Problem

What is the slope of a line perpendicular to y=53x2y = \frac{5}{3}x - 2?

Original slope: 53\frac{5}{3}

Perpendicular slope: 35-\frac{3}{5}

Solution

Worked Example: SAT-Style

Problem

Line pp passes through (4,1)(4, -1) and is perpendicular to 2xy=52x - y = 5. What is the equation of line pp?

Convert: y=2x5y = 2x - 5. Slope =2= 2.

Perpendicular slope: 12-\frac{1}{2}

Point-slope: y(1)=12(x4)y - (-1) = -\frac{1}{2}(x - 4)

y+1=12x+2y + 1 = -\frac{1}{2}x + 2

y=12x+1y = -\frac{1}{2}x + 1

Solution

Worked Example: Example 4

Problem

Are the lines y=4x+1y = 4x + 1 and 8x2y=68x - 2y = 6 parallel, perpendicular, or neither?

First line: slope =4= 4

Second line: 2y=8x+6-2y = -8x + 6y=4x3y = 4x - 3. Slope =4= 4.

Same slope, different y-intercept → parallel.

Solution

Worked Example: Example 5

Problem

Are the lines y=23x+5y = \frac{2}{3}x + 5 and y=32x1y = -\frac{3}{2}x - 1 perpendicular?

Product of slopes: 23×(32)=1\frac{2}{3} \times (-\frac{3}{2}) = -1

Yes, perpendicular.

Solution

Practice Problems

  1. Problem 1

    What is the slope of a line parallel to 4x+2y=104x + 2y = 10?

    Problem 2

    What is the slope of a line perpendicular to y=54x+3y = -\frac{5}{4}x + 3?

    Problem 3

    Write the equation of the line parallel to y=3x+7y = -3x + 7 that passes through (2,4)(2, 4).

    Problem 4

    Write the equation of the line perpendicular to x+3y=9x + 3y = 9 that passes through (3,2)(3, -2).

    Problem 5

    Are the lines y=12x+3y = \frac{1}{2}x + 3 and 2y+4x=82y + 4x = 8 parallel, perpendicular, or neither?

    Problem 6

    A line is perpendicular to y=5y = 5 and passes through (2,3)(2, 3). What is its equation?

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Common Mistakes

  • Forgetting the negative in negative reciprocal. The perpendicular slope to 22 is 12-\frac{1}{2}, not 12\frac{1}{2}.
  • Only taking the reciprocal. You need BOTH the negative AND the reciprocal.
  • Not converting to slope-intercept form before reading the slope. In 3x+4y=123x + 4y = 12, the slope is NOT 3.
  • Thinking "same slope" means the same line. Parallel lines have the same slope but different y-intercepts. Same slope AND same y-intercept means the same line.
  • Confusing the conditions. Parallel → same slope. Perpendicular → slopes multiply to 1-1.

Frequently Asked Questions

Can perpendicular lines have the same y-intercept?

Yes! Perpendicular lines can cross at any point, including on the y-axis.

What's the perpendicular slope of a horizontal line?

A horizontal line has slope 0. The perpendicular would be a vertical line (undefined slope). You can't express it as y=mx+by = mx + b — it's x=kx = k.

How often does this appear on the SAT?

Very frequently. Parallel and perpendicular relationships appear in pure algebra questions, coordinate geometry, and even some word problems.

Can two lines be both parallel and perpendicular?

No. That's impossible (except in degenerate cases). Parallel lines have the same slope; perpendicular lines have slopes that multiply to 1-1.

What if I'm given two points instead of a slope?

Calculate the slope from the two points first, then use the parallel/perpendicular relationship.

Key Takeaways

  • Parallel lines: same slope, different y-intercepts. m1=m2m_1 = m_2.

  • Perpendicular lines: slopes are negative reciprocals. m1m2=1m_1 \cdot m_2 = -1.

  • To write an equation of a related line: find the appropriate slope, then use point-slope form.

  • Quick check: multiply slopes — if the product is 1-1, they're perpendicular.

  • Always convert to slope-intercept form first to easily identify the slope.

  • Horizontal ⊥ vertical is a special case to remember.

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