Literal Equations and Formulas

Learn to rearrange formulas and solve literal equations for the Digital SAT. Isolate any variable with step-by-step methods.

A literal equation is an equation that contains two or more variables. Instead of solving for a numerical answer, you solve for one variable in terms of the others. The SAT frequently asks you to rearrange formulas — isolating a specific variable from a physics formula, geometry formula, or a general algebraic expression.

This skill is essential because many SAT problems present a formula and then ask you to express one variable in terms of others. Examples include rearranging d=rtd = rt to find tt, or isolating ww from P=2l+2wP = 2l + 2w.

Core Concepts

What Is a Literal Equation?

A literal equation contains multiple variables (letters) rather than a single unknown. Examples:

  • d=rtd = rt (distance = rate × time)
  • A=12bhA = \frac{1}{2}bh (area of a triangle)
  • C=59(F32)C = \frac{5}{9}(F - 32) (Celsius to Fahrenheit conversion)
  • y=mx+by = mx + b (slope-intercept form)

The Key Principle

Treat the variable you're solving for as the "unknown" and treat every other variable as if it were a number. Then use the same inverse operations you'd use for a regular equation.

Solving for a Variable: Step by Step

  1. Identify which variable to isolate.
  2. Use inverse operations to get that variable alone.
  3. Other variables are treated as constants.

Example: Solve d=rtd = rt for tt.

Divide both sides by rr:

t=drt = \frac{d}{r}

Example: Solve A=12bhA = \frac{1}{2}bh for hh.

Multiply both sides by 2: 2A=bh2A = bh

Divide by bb: h=2Abh = \frac{2A}{b}

Formulas with Multiple Steps

Example: Solve P=2l+2wP = 2l + 2w for ww.

Subtract 2l2l: P2l=2wP - 2l = 2w

Divide by 2: w=P2l2w = \frac{P - 2l}{2}

Formulas with the Variable in a Fraction

Example: Solve 1a+1b=1c\frac{1}{a} + \frac{1}{b} = \frac{1}{c} for cc.

1c=1a+1b=a+bab\frac{1}{c} = \frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab}

Take the reciprocal: c=aba+bc = \frac{ab}{a + b}

Formulas with the Variable Inside Brackets

Example: Solve C=59(F32)C = \frac{5}{9}(F - 32) for FF.

Multiply by 95\frac{9}{5}: 9C5=F32\frac{9C}{5} = F - 32

Add 32: F=9C5+32F = \frac{9C}{5} + 32

Formulas with the Variable Squared

Example: Solve A=πr2A = \pi r^2 for rr (where r>0r > 0).

Divide by π\pi: Aπ=r2\frac{A}{\pi} = r^2

Take the square root: r=Aπr = \sqrt{\frac{A}{\pi}}

Strategy Tips

Tip 1: Treat Other Variables Like Numbers

If you're solving 2x+3y=122x + 3y = 12 for xx, pretend 3y3y is just a number. Subtract it: 2x=123y2x = 12 - 3y. Divide by 2: x=123y2x = \frac{12 - 3y}{2}.

Tip 2: Be Systematic

Follow the same steps as a regular equation: undo operations in reverse order.

Tip 3: Watch for the Variable in the Denominator

If the variable you want is in a denominator, multiply both sides by that variable to "free" it.

Tip 4: Factor When the Variable Appears More Than Once

If the target variable appears in multiple terms, collect those terms and factor it out.

Example: Solve ax+bx=cax + bx = c for xx.

Factor: x(a+b)=cx(a + b) = c

Divide: x=ca+bx = \frac{c}{a + b}

Tip 5: Check Your Answer by Substituting

Plug your rearranged formula back into the original to verify it's consistent.

Worked Example: Example 1

Problem

The formula V=lwhV = lwh gives the volume of a rectangular prism. Solve for hh.

Divide both sides by lwlw:

h=Vlwh = \frac{V}{lw}

Solution

Worked Example: Example 2

Problem

Solve y=mx+by = mx + b for mm.

Subtract bb: yb=mxy - b = mx

Divide by xx: m=ybxm = \frac{y - b}{x}

Solution

Worked Example: Example 3

Problem

Solve S=n(a+l)2S = \frac{n(a + l)}{2} for aa.

Multiply by 2: 2S=n(a+l)2S = n(a + l)

Divide by nn: 2Sn=a+l\frac{2S}{n} = a + l

Subtract ll: a=2Snla = \frac{2S}{n} - l

Solution

Worked Example: Example 4

Problem

Solve T=2πLgT = 2\pi\sqrt{\frac{L}{g}} for LL.

Divide by 2π2\pi: T2π=Lg\frac{T}{2\pi} = \sqrt{\frac{L}{g}}

Square both sides: T24π2=Lg\frac{T^2}{4\pi^2} = \frac{L}{g}

Multiply by gg: L=gT24π2L = \frac{gT^2}{4\pi^2}

Solution

Worked Example: SAT-Style

Problem

The equation 3x2y=183x - 2y = 18 relates xx and yy. Which of the following expresses yy in terms of xx?

Subtract 3x3x: 2y=183x-2y = 18 - 3x

Divide by 2-2: y=183x2=3x182y = \frac{18 - 3x}{-2} = \frac{3x - 18}{2}

Or equivalently: y=32x9y = \frac{3}{2}x - 9

Solution

Practice Problems

  1. Problem 1

    Solve E=mc2E = mc^2 for mm.

    Problem 2

    Solve ax+by=cax + by = c for yy.

    Problem 3

    Solve xa+yb=1\frac{x}{a} + \frac{y}{b} = 1 for yy.

    Problem 4

    Solve I=VRI = \frac{V}{R} for RR.

    Problem 5

    Solve s=ut+12at2s = ut + \frac{1}{2}at^2 for aa.

    Problem 6

    Solve 3(x+k)=2(yk)3(x + k) = 2(y - k) for kk.

Want to check your answers and get step-by-step solutions?

Get it on Google PlayDownload on the App Store

Common Mistakes

  • Not distributing before isolating. If the target variable is inside brackets, you may need to expand first.
  • Dividing incorrectly with multi-term expressions. In w=P2l2w = \frac{P - 2l}{2}, you divide the entire expression P2lP - 2l by 2, not just PP.
  • Forgetting that square root introduces ±. When taking a square root, consider context. For physical quantities (lengths, areas), take the positive root.
  • Not factoring when the variable appears twice. If xx appears in two terms, you must factor it out.
  • Flipping only part of a fraction. When taking the reciprocal of a+bc\frac{a + b}{c}, you get ca+b\frac{c}{a + b}, not ca+cb\frac{c}{a} + \frac{c}{b}.

Frequently Asked Questions

How are literal equations different from regular equations?

The technique is identical. The only difference is that your answer contains variables instead of a number.

Will I need to rearrange complex physics formulas on the SAT?

The SAT uses formulas that look complex but typically require only two or three algebraic steps. You won't need advanced physics knowledge.

What if the variable I'm solving for appears more than once?

Collect all terms containing that variable on one side, factor it out, then divide.

Do I need to memorise any formulas for the SAT?

The SAT provides a reference sheet with key geometry formulas. However, you should know y=mx+by = mx + b, d=rtd = rt, and basic area/volume formulas from memory.

Can I cross-multiply with literal equations?

Yes, if the equation has one fraction on each side, cross-multiplying works perfectly.

Key Takeaways

  • Literal equations use the same inverse-operation method as regular equations.

  • Treat all other variables as constants — focus only on the one you're solving for.

  • When the target variable appears multiple times, collect its terms and factor.

  • Clear fractions by multiplying by the denominator.

  • Check your rearrangement by substituting back.

  • This skill is highly testable on the SAT — practise with real formulas.

Ready to Ace Your SAT math?

Get instant step-by-step solutions to any problem. Snap a photo and learn with Tutor AI — your personal exam prep companion.

Get it on Google PlayDownload on the App Store