Simplifying Rational Expressions

Simplify, multiply, and divide algebraic fractions for the Digital SAT. Factor, cancel common terms, and avoid common errors.

Rational expressions are fractions where the numerator and/or denominator contain polynomials. The Digital SAT tests your ability to simplify these expressions by factoring and cancelling, as well as to multiply and divide them. This topic combines your factoring skills with fraction operations.

Core Concepts

What Is a Rational Expression?

A rational expression is a fraction with polynomials in the numerator and denominator:

x29x2+5x+6\frac{x^2 - 9}{x^2 + 5x + 6}

Simplifying by Factoring and Cancelling

  1. Factor the numerator.
  2. Factor the denominator.
  3. Cancel common factors.

Example: x29x2+5x+6=(x+3)(x3)(x+3)(x+2)=x3x+2\frac{x^2 - 9}{x^2 + 5x + 6} = \frac{(x+3)(x-3)}{(x+3)(x+2)} = \frac{x-3}{x+2}

(Valid for x3x \neq -3 and x2x \neq -2)

Restrictions on the Variable

The denominator cannot equal zero. After cancelling, note the original restrictions.

For x29x2+5x+6\frac{x^2 - 9}{x^2 + 5x + 6}: x3x \neq -3 and x2x \neq -2.

Multiplying Rational Expressions

AB×CD=ACBD\frac{A}{B} \times \frac{C}{D} = \frac{AC}{BD}

Factor everything first, then cancel before multiplying:

x+2x21×x1x+2=(x+2)(x+1)(x1)×(x1)(x+2)=1x+1\frac{x+2}{x^2-1} \times \frac{x-1}{x+2} = \frac{(x+2)}{(x+1)(x-1)} \times \frac{(x-1)}{(x+2)} = \frac{1}{x+1}

Dividing Rational Expressions

Flip the second fraction and multiply:

AB÷CD=AB×DC\frac{A}{B} \div \frac{C}{D} = \frac{A}{B} \times \frac{D}{C}

Adding and Subtracting Rational Expressions

Find a common denominator, combine numerators:

3x+1+2x1=3(x1)+2(x+1)(x+1)(x1)=5x1x21\frac{3}{x+1} + \frac{2}{x-1} = \frac{3(x-1) + 2(x+1)}{(x+1)(x-1)} = \frac{5x - 1}{x^2 - 1}

Strategy Tips

Tip 1: Factor EVERYTHING First

Never cancel individual terms — only cancel common factors. x2+xx=x(x+1)x=x+1\frac{x^2 + x}{x} = \frac{x(x+1)}{x} = x + 1, not x+1x + 1 from cancelling the x2x^2.

Tip 2: Cancel Before Multiplying

Cross-cancelling between numerators and denominators keeps the numbers manageable.

Tip 3: Don't Cancel Terms — Cancel Factors

x+3x+535\frac{x + 3}{x + 5} \neq \frac{3}{5}. You can only cancel when the entire numerator and denominator share a common FACTOR.

Tip 4: State Restrictions

The SAT may ask for values where an expression is undefined. Set each denominator factor equal to zero.

Tip 5: LCD for Addition/Subtraction

Finding the least common denominator (LCD) is key for adding/subtracting rational expressions.

Worked Example: Example 1

Problem

Simplify x24x2+4x+4\frac{x^2 - 4}{x^2 + 4x + 4}.

=(x+2)(x2)(x+2)2=x2x+2= \frac{(x+2)(x-2)}{(x+2)^2} = \frac{x-2}{x+2}

Solution

Worked Example: Example 2

Problem

Simplify 2x2+6x4x\frac{2x^2 + 6x}{4x}.

=2x(x+3)4x=x+32= \frac{2x(x + 3)}{4x} = \frac{x + 3}{2}

Solution

Worked Example: Example 3

Problem

Multiply: x21x+3x+3x+1\frac{x^2-1}{x+3} \cdot \frac{x+3}{x+1}

=(x+1)(x1)x+3x+3x+1=x1= \frac{(x+1)(x-1)}{x+3} \cdot \frac{x+3}{x+1} = x - 1

Solution

Worked Example: SAT-Style

Problem

Which is equivalent to x25x+6x24\frac{x^2 - 5x + 6}{x^2 - 4}?

=(x2)(x3)(x+2)(x2)=x3x+2= \frac{(x-2)(x-3)}{(x+2)(x-2)} = \frac{x-3}{x+2}

Solution

Worked Example: Example 5

Problem

For what value of xx is x2+2x8x216\frac{x^2 + 2x - 8}{x^2 - 16} undefined?

x216=(x+4)(x4)=0x^2 - 16 = (x+4)(x-4) = 0 when x=4x = 4 or x=4x = -4.

The expression is undefined at x=4x = 4 and x=4x = -4.

Solution

Practice Problems

  1. Problem 1

    Simplify x225x210x+25\frac{x^2 - 25}{x^2 - 10x + 25}.

    Problem 2

    Simplify 3x2126x+12\frac{3x^2 - 12}{6x + 12}.

    Problem 3

    Multiply x2+x6x+1x+1x2\frac{x^2 + x - 6}{x + 1} \cdot \frac{x + 1}{x - 2}.

    Problem 4

    Divide x21x+3÷x1x2+3x\frac{x^2 - 1}{x + 3} \div \frac{x - 1}{x^2 + 3x}.

    Problem 5

    For what values of xx is x+5x29\frac{x + 5}{x^2 - 9} undefined?

    Problem 6

    Simplify 2x+3x+1\frac{2}{x} + \frac{3}{x + 1}.

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Common Mistakes

  • Cancelling terms instead of factors. x+3x+535\frac{x + 3}{x + 5} \neq \frac{3}{5}. You can only cancel when x+3x + 3 divides both numerator and denominator.
  • Forgetting to factor fully. Always factor both numerator and denominator completely before cancelling.
  • Not stating restrictions. Cancelled factors still create restrictions on the variable.
  • Sign errors with difference of squares. x33x=x3(x3)=1\frac{x - 3}{3 - x} = \frac{x - 3}{-(x - 3)} = -1, not 11.
  • Errors with LCD in addition/subtraction. Make sure every term gets multiplied correctly.

Frequently Asked Questions

Can I cancel $x$ from $\frac{x + 5}{x}$?

No. xx is a term in the numerator, not a factor. x+5x + 5 does not have xx as a factor.

Is $\frac{0}{5} = 0$? Is $\frac{5}{0}$ undefined?

Yes and yes. A fraction with 0 in the numerator equals 0. A fraction with 0 in the denominator is undefined.

How does the SAT test rational expressions?

"Which is equivalent to..." questions, finding undefined values, and simplifying complex expressions.

What if the numerator and denominator share a factor like $(3-x)$ and $(x-3)$?

(3x)=(x3)(3-x) = -(x-3), so 3xx3=1\frac{3-x}{x-3} = -1. Remember this sign trick.

Do I need to add/subtract rational expressions on the SAT?

Occasionally. It's less common than simplifying/multiplying but does appear.

Key Takeaways

  • Factor numerator and denominator completely, then cancel common factors.

  • Cancel factors, not terms. Only whole factors that appear in both can be cancelled.

  • Multiply: factor → cancel → multiply remaining.

  • Divide: flip and multiply.

  • Restrictions: the variable cannot equal values that make any denominator zero.

  • Watch for the sign trick: (ab)=(ba)(a-b) = -(b-a).

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