A linear-quadratic system consists of one linear equation and one quadratic equation. Graphically, this is a line intersecting a parabola. Such a system can have 0, 1, or 2 solutions depending on the relative positions of the line and parabola. The Digital SAT tests this by asking you to solve the system, find the number of solutions, or determine a parameter value.
Core Concepts
Three Cases
| Case | Graphically | Solutions |
|---|---|---|
| Line intersects parabola twice | 2 intersection points | 2 solutions |
| Line is tangent to parabola | 1 intersection point | 1 solution |
| Line misses parabola | No intersection | 0 solutions |
Solving by Substitution
- The linear equation is usually already solved for .
- Substitute into the quadratic equation.
- Solve the resulting quadratic (by factoring or quadratic formula).
- Find the corresponding -values.
Example: and
Set equal:
→ . → .
Solutions: and .
Using the Discriminant
After setting the equations equal, you get a quadratic. Apply the discriminant to determine the number of solutions without actually solving:
- : 2 intersection points
- : 1 intersection point (tangent)
- : 0 intersection points
Finding Parameters
Example: For what value of is tangent to ?
→
For tangency: →
Strategy Tips
Tip 1: Substitute to Eliminate
Always substitute the linear equation into the quadratic. This gives a single-variable quadratic.
Tip 2: Use the Discriminant for "How Many Solutions"
If the question only asks for the number of solutions, don't solve — just compute the discriminant.
Tip 3: Remember to Find Both Coordinates
After finding -values, plug back to get -values. The solution is an ordered pair.
Tip 4: Graph on Desmos
Quickly visualise the intersection by graphing both equations.
Tip 5: If Isn't Isolated
If neither equation is solved for a variable, solve the simpler one (usually the linear equation) first.
Worked Example: Example 1
Solve and .
→ →
and
Worked Example: Example 2
How many solutions? and
→
→ 2 solutions
Worked Example: SAT-Style
The line is tangent to the parabola . What is ?
→
→
Worked Example: Example 4
Solve and .
→ →
and
Solutions: and .
Worked Example: Example 5
Does intersect ?
→ — impossible over reals.
No intersection.
Practice Problems
Problem 1
Solve and .
Problem 2
How many solutions? and .
Problem 3
For what value of does intersect at exactly one point?
Problem 4
Solve and .
Problem 5
A line passes through two points on . Find the points when .
Problem 6
Does the line intersect the parabola ?
Want to check your answers and get step-by-step solutions?
Common Mistakes
- Solving the wrong equation. Always substitute the linear into the quadratic (or set them equal).
- Forgetting to find -values. The solutions are points , not just -values.
- Misidentifying the number of solutions. Use the discriminant of the resulting quadratic, not the original equations.
- Errors in rearranging. When setting equal, be careful moving all terms to one side.
- Not checking solutions. Plug back into both original equations.
Frequently Asked Questions
Can a line intersect a parabola more than twice?
No. A line can intersect a parabola at most 2 times.
What if the system has a quadratic and another quadratic?
The SAT primarily tests linear-quadratic systems. Quadratic-quadratic systems are rare.
How is tangency related to the discriminant?
A line is tangent to a parabola when the resulting quadratic has (one repeated solution).
Can I graph this on Desmos?
Absolutely — graph both equations and visually see the intersection points.
Is this under Algebra or Advanced Math on the SAT?
Advanced Math. It's one of the harder topics in the section.
Key Takeaways
Substitute the linear equation into the quadratic to get a single-variable quadratic.
Use the discriminant to find the number of solutions without solving.
A line can intersect a parabola at 0, 1, or 2 points.
means tangent (exactly one solution).
Always find both coordinates of each solution.
For parameter questions, set for tangency conditions.
