Nuclear Fission and Fusion

E = mc²; binding energy per nucleon; fission chain reactions; fusion conditions

# Nuclear Fission and Fusion — IB Physics

1. Mass-Energy Equivalence

E=mc2E = mc^2

11 u =931.5= 931.5 MeV/c².

2. Mass Defect and Binding Energy

Mass defect (Δm\Delta m): difference between mass of separate nucleons and assembled nucleus.

Binding energy: BE=Δm×c2BE = \Delta m \times c^2 — energy needed to separate the nucleus into individual nucleons.

BE per nucleon: measures stability. Peak at Fe-56 (~8.8 MeV).

3. Fission

Heavy nucleus splits into lighter nuclei + neutrons + energy.

92235U+01n56141Ba+3692Kr+301n+200 MeV^{235}_{92}U + ^1_0 n \to ^{141}_{56}Ba + ^{92}_{36}Kr + 3^1_0 n + \sim 200 \text{ MeV}

Chain reaction: Each fission releases 2-3 neutrons → can trigger more fissions.

Reactor: Moderator (slow neutrons), control rods (absorb neutrons), coolant.

4. Fusion

Light nuclei combine: 2H+3H4He+1n+17.6^2 H + ^3 H \to ^4 He + ^1 n + 17.6 MeV.

Requires: >100 million K, high density, long confinement time.

Advantages: abundant fuel, less waste, no CO₂, no meltdown risk. Challenges: containing plasma at extreme temperatures.

5. Why Both Release Energy

Both move products toward Fe-56 (higher BE per nucleon). The increase in BE per nucleon × number of nucleons = energy released.

Worked Example: Energy from Mass Defect

Problem

In the D-T fusion: mass before = 2.01410 + 3.01605 = 5.03015 u. Mass after = 4.00260 + 1.00867 = 5.01127 u. Δm=0.01888\Delta m = 0.01888 u = 0.01888×931.5=17.60.01888 \times 931.5 = 17.6 MeV ✓

Solution

Worked Example: Example 2

Problem

Fe-56 has BE = 492 MeV. BE/nucleon = 492/56 = 8.79 MeV. U-235 has BE/nucleon ≈ 7.59 MeV. Difference ≈ 1.2 MeV/nucleon. For 235 nucleons: ~280 MeV → but split into 2 roughly equal fragments plus neutrons, giving about 200 MeV total.

Solution

7. Practice Questions

    1. Explain what is meant by binding energy per nucleon and why Fe-56 is significant. (3 marks)
    1. Calculate the energy released when 1 kg of U-235 undergoes complete fission (200 MeV per event). (3 marks)
    1. Explain why fusion requires extremely high temperatures. (2 marks)
    1. Compare fission and fusion in terms of fuel, waste, and energy. (4 marks)

    Answers

    1. BE per nucleon = total binding energy divided by number of nucleons. It measures how tightly nucleons are bound (stability). Fe-56 has the highest BE/nucleon, making it the most stable nucleus. Nuclei lighter than Fe release energy by fusion; heavier than Fe release energy by fission.

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Summary

  • E=mc2E = mc^2; 11 u = 931.5 MeV
  • BE per nucleon peaks at Fe-56
  • Fission: heavy → lighter + energy; chain reaction; reactor controls
  • Fusion: light → heavier + energy; needs extreme T for plasma

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