Geometric Sequences and Series

Master geometric sequences and series for IB Maths. Find terms, sums, and the sum to infinity.

Geometric sequences have a constant ratio between consecutive terms. The sum to infinity is a key concept for IB Math.

Core Formulas

un=u1rn1u_n = u_1 \cdot r^{n-1} — nth term

Sn=u1(1rn)1rS_n = \frac{u_1(1-r^n)}{1-r} — sum of first nn terms (r1r \neq 1)

S=u11rS_\infty = \frac{u_1}{1-r} — sum to infinity (r<1|r| < 1)

Worked Example: Example 1

Problem

u1=3u_1 = 3, r=2r = 2. u6=325=96u_6 = 3 \cdot 2^5 = 96. S6=3(164)12=189S_6 = \frac{3(1-64)}{1-2} = 189.

Solution

Worked Example: Example 2

Problem

u1=100u_1 = 100, r=0.8r = 0.8. S=1000.2=500S_\infty = \frac{100}{0.2} = 500.

Solution

Worked Example: Compound Interest

Problem

£5000 at 4% p.a. for 10 years: 5000×1.0410=£7401.225000 \times 1.04^{10} = £7401.22.

Solution

IB Exam Tips

  • Always state whether r<1|r| < 1 when using SS_\infty.
  • Common application: compound interest, depreciation, population.

Practice Problems

    1. GP: u1=8u_1 = 8, r=12r = \frac{1}{2}. Find SS_\infty.
    1. u3=12u_3 = 12, u6=32u_6 = \frac{3}{2}. Find rr and u1u_1.
    1. How many terms of 1, 3, 9, ... are needed for Sn>1000S_n > 1000?

Want to check your answers and get step-by-step solutions?

Get it on Google PlayDownload on the App Store

Key Takeaways

  • un=u1rn1u_n = u_1 r^{n-1}. S=u11rS_\infty = \frac{u_1}{1-r} (only if r<1|r| < 1).

  • Divide consecutive terms to find rr.

Ready to Ace Your IB maths?

Get instant step-by-step solutions to any problem. Snap a photo and learn with Tutor AI — your personal exam prep companion.

Get it on Google PlayDownload on the App Store