Exponential Growth and Decay

Model real-world scenarios with exponential functions for IB Maths. Apply to population, radioactive decay, and finance.

Exponential models describe quantities that grow or decay by a constant percentage. This is heavily tested in IB Math AI and AA.

Models

Growth: y=abty = a \cdot b^t where b>1b > 1

Population doubling: P=P02t/dP = P_0 \cdot 2^{t/d} where dd = doubling time.

Decay: y=abty = a \cdot b^t where 0<b<10 < b < 1

Half-life: N=N0(12)t/hN = N_0 \cdot \left(\frac{1}{2}\right)^{t/h} where hh = half-life.

Continuous: y=aekty = ae^{kt}

k>0k > 0: growth. k<0k < 0: decay.

Worked Example: Population

Problem

Population 5000 grows 3% p.a. After 20 years: 5000×1.032090315000 \times 1.03^{20} \approx 9031.

Solution

Worked Example: Half-life

Problem

Substance with half-life 8 hours. Starting with 200g, after 24 hours: 200×(12)3=25200 \times (\frac{1}{2})^3 = 25g.

Solution

Worked Example: Finding k

Problem

Bacteria: 100 at t=0t=0, 450 at t=5t=5. 450=100e5k450 = 100e^{5k}k=ln4.550.301k = \frac{\ln 4.5}{5} \approx 0.301.

Solution

IB Exam Tips

  • Show the model equation clearly.
  • Use GDC for solving, but show algebraic setup.
  • Units and context matter for full marks.

Practice Problems

    1. A car depreciates 15% per year from £25,000. Value after 6 years?
    1. A substance has half-life 5 years. How long until 10% remains?

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Key Takeaways

  • Growth: b>1b > 1 or k>0k > 0. Decay: 0<b<10 < b < 1 or k<0k < 0.

  • Half-life: multiply by 12\frac{1}{2} per period.

  • Use logs to find time.

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