Exponent and Logarithm Laws

Apply exponent and logarithm laws for IB Maths. Solve exponential and logarithmic equations.

Exponent and logarithm laws are fundamental tools in IB Mathematics, used in solving equations, modelling, and calculus.

Exponent Laws

aman=am+na^m \cdot a^n = a^{m+n}, aman=amn\frac{a^m}{a^n} = a^{m-n}, (am)n=amn(a^m)^n = a^{mn}

a0=1a^0 = 1, an=1ana^{-n} = \frac{1}{a^n}, am/n=amna^{m/n} = \sqrt[n]{a^m}

Logarithm Laws

loga(xy)=logax+logay\log_a(xy) = \log_a x + \log_a y

loga(xy)=logaxlogay\log_a(\frac{x}{y}) = \log_a x - \log_a y

loga(xn)=nlogax\log_a(x^n) = n\log_a x

logaa=1\log_a a = 1, loga1=0\log_a 1 = 0

logax=logbxlogba\log_a x = \frac{\log_b x}{\log_b a} (change of base)

Natural Logarithm

lnx=logex\ln x = \log_e x. elnx=xe^{\ln x} = x. ln(ex)=x\ln(e^x) = x.

Solving Equations

3x=203^x = 20x=ln20ln32.73x = \frac{\ln 20}{\ln 3} \approx 2.73

ln(2x+1)=4\ln(2x + 1) = 42x+1=e42x + 1 = e^4x=e41226.8x = \frac{e^4 - 1}{2} \approx 26.8

Practice Problems

    1. Solve 52x1=1255^{2x-1} = 125.
    1. Solve log2(x)+log2(x3)=2\log_2(x) + \log_2(x-3) = 2.
    1. Simplify log327log39\log_3 27 - \log_3 9.

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Key Takeaways

  • Logs undo exponents: logab=c\log_a b = cac=ba^c = b.

  • Three log laws + change of base.

  • ln\ln and ee are inverses.

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