The Binomial Theorem

Expand expressions using the binomial theorem for IB Maths. Find specific terms and apply Pascal's triangle.

The binomial theorem expands (a+b)n(a+b)^n for positive integer nn. It's in the IB data booklet.

The Formula

(a+b)n=r=0n(nr)anrbr(a+b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r

(nr)=n!r!(nr)!\binom{n}{r} = \frac{n!}{r!(n-r)!}

Pascal's Triangle

Row nn gives the coefficients. Row 4: 1, 4, 6, 4, 1.

Finding a Specific Term

The (r+1)(r+1)th term: Tr+1=(nr)anrbrT_{r+1} = \binom{n}{r} a^{n-r} b^r.

Example

Find the coefficient of x3x^3 in (2x+3)5(2x + 3)^5.

Tr+1=(5r)(2x)5r(3)rT_{r+1} = \binom{5}{r}(2x)^{5-r}(3)^r. For x3x^3: 5r=35-r = 3r=2r = 2.

T3=(52)(2x)3(3)2=108x39=720x3T_3 = \binom{5}{2}(2x)^3(3)^2 = 10 \cdot 8x^3 \cdot 9 = 720x^3. Coefficient: 720.

Worked Example: Example 1

Problem

(1+x)6(1+x)^6: expand first 4 terms. =1+6x+15x2+20x3+...= 1 + 6x + 15x^2 + 20x^3 + ...

Solution

Worked Example: Example 2

Problem

Find the constant term in (x+2x)6(x + \frac{2}{x})^6.

Tr+1=(6r)x6r(2x)r=(6r)2rx62rT_{r+1} = \binom{6}{r}x^{6-r}(\frac{2}{x})^r = \binom{6}{r}2^r x^{6-2r}.

Constant: 62r=06-2r = 0r=3r = 3. T4=(63)(8)=160T_4 = \binom{6}{3}(8) = 160.

Solution

Practice Problems

    1. Expand (3+x)4(3 + x)^4.
    1. Find the coefficient of x4x^4 in (12x)7(1-2x)^7.
    1. Find the constant term in (x2+1x)9(x^2 + \frac{1}{x})^9.

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Key Takeaways

  • Formula is in the data booklet.

  • Use Tr+1=(nr)anrbrT_{r+1} = \binom{n}{r}a^{n-r}b^r for specific terms.

  • Set the power of xx equal to what you need and solve for rr.

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