Gas Pressure and Temperature

Particle motion and pressure; pV = constant; absolute zero and Kelvin

# Gas Pressure and Temperature — GCSE Physics

Gas pressure is caused by billions of tiny particles constantly colliding with the walls of their container. Understanding how temperature and volume affect gas pressure is essential for GCSE Physics.


1. What Causes Gas Pressure?

Gas particles move rapidly and randomly in all directions. When they collide with the walls of their container, they exert a force on the wall. The total force of billions of these collisions per second creates gas pressure.

Pressure=Total force from collisionsArea of container walls\text{Pressure} = \frac{\text{Total force from collisions}}{\text{Area of container walls}}


2. Temperature and Pressure (Constant Volume)

When the temperature of a gas increases (at constant volume):

  1. Particles gain kinetic energy → move faster
  2. They collide with the walls more frequently and with greater force
  3. Therefore, the pressure increases

Relationship: PTP \propto T (pressure is directly proportional to absolute temperature, at constant volume)


3. Volume and Pressure (Constant Temperature)

Boyle's Law: For a fixed mass of gas at constant temperature:

P1V1=P2V2\boxed{P_1 V_1 = P_2 V_2}

Or: PV=constantPV = \text{constant}

When volume decreases (at constant temperature):

  1. Particles are in a smaller space
  2. They hit the walls more frequently
  3. Pressure increases

Pressure and volume are inversely proportional (at constant temperature).


4. Absolute Zero and the Kelvin Scale

Absolute zero is the lowest possible temperature: −273°C (or 0 K).

At absolute zero, particles have minimum internal energy — they (theoretically) stop moving entirely.

Converting Temperature

T(K)=T(°C)+273T(K) = T(°C) + 273 T(°C)=T(K)273T(°C) = T(K) - 273

Celsius (°C) Kelvin (K)
−273 0
0 273
20 293
100 373

Important: Gas law calculations must use Kelvin, not Celsius.


5. Pressure, Volume, and Temperature Combined

For a fixed mass of gas:

P1V1T1=P2V2T2\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

Where TT is in Kelvin.


Worked Example: Boyle's Law

Problem

Question: A gas has a volume of 2.0 m³ at a pressure of 100 kPa. The volume is reduced to 0.5 m³ at constant temperature. Calculate the new pressure.

P1V1=P2V2P_1 V_1 = P_2 V_2 100×2.0=P2×0.5100 \times 2.0 = P_2 \times 0.5 P2=200/0.5=400 kPaP_2 = 200/0.5 = 400 \text{ kPa}

Solution

Worked Example: Temperature and Pressure

Problem

Question: A sealed container of gas is at 20°C and 100 kPa. It is heated to 80°C. Calculate the new pressure.

T1=20+273=293T_1 = 20 + 273 = 293 K, T2=80+273=353T_2 = 80 + 273 = 353 K

P1T1=P2T2    P2=P1×T2T1=100×353293=120.5 kPa\frac{P_1}{T_1} = \frac{P_2}{T_2} \implies P_2 = P_1 \times \frac{T_2}{T_1} = 100 \times \frac{353}{293} = 120.5 \text{ kPa}

Solution

Worked Example: Converting Temperature

Problem

Question: Convert 350 K to Celsius.

T=350273=77°CT = 350 - 273 = 77°C


Solution

7. Practice Questions

    1. Explain, using the particle model, why gas pressure increases when temperature increases (at constant volume). (3 marks)
    1. A gas occupies 4.0 litres at 200 kPa. Calculate the volume at 800 kPa (constant temperature). (2 marks)
    1. Convert −40°C to Kelvin. (1 mark)
    1. A gas is at 300 K and 150 kPa. It is cooled to 200 K at constant volume. Calculate the new pressure. (2 marks)
    1. Why must gas law calculations use Kelvin, not Celsius? (2 marks)

    Answers

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Summary

  • Gas pressure is caused by particle collisions with container walls
  • Higher temperature → faster particles → more frequent/harder collisions → higher pressure
  • Boyle's Law: P1V1=P2V2P_1V_1 = P_2V_2 (constant temperature)
  • Absolute zero: −273°C = 0 K (minimum energy)
  • Kelvin = Celsius + 273; always use Kelvin in gas calculations

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