Electric Charge & Force

AP Physics 1 review of electric charge, Coulomb's law, conductors and insulators, and charge conservation.

# Electric Charge & Force — AP Physics 1

Electricity begins with electric charge and the forces between charges. AP Physics 1 covers the basics: charge properties, Coulomb's law, and the behavior of conductors and insulators. These concepts lay the groundwork for circuits and more advanced electrostatics in AP Physics 2.

Key Concepts

Electric Charge

  • Two types: positive and negative.
  • Like charges repel; unlike charges attract.
  • Charge is quantized: q=neq = ne where e=1.6×1019 Ce = 1.6 \times 10^{-19}\ \text{C}.
  • Charge is conserved: total charge in an isolated system remains constant.

Conductors and Insulators

  • Conductors: electrons move freely (metals). Charge distributes on the surface.
  • Insulators: electrons are bound in place (rubber, glass).
  • Charging methods: friction, contact, induction.

Coulomb's Law

F=kq1q2r2F = k\frac{|q_1||q_2|}{r^2} where k=8.99×109 N\cdotpm2/C2k = 8.99 \times 10^9\ \text{N·m}^2/\text{C}^2.

  • Follows an inverse-square law (like gravity).
  • Coulomb's law gives the magnitude; direction is along the line connecting the charges.

Superposition

The net force on a charge is the vector sum of all individual Coulomb forces from other charges.

Comparing Electrostatic and Gravitational Forces

  • Both are inverse-square laws.
  • Coulomb force can be attractive or repulsive; gravity is always attractive.
  • The electrostatic force is enormously stronger than gravity for fundamental particles.

Worked Example

Problem: Two charges, q1=+3 μCq_1 = +3\ \mu\text{C} and q2=5 μCq_2 = -5\ \mu\text{C}, are separated by 0.2 m0.2\ \text{m}. Find the force between them.

Solution:

F=kq1q2r2=(8.99×109)(3×106)(5×106)(0.2)2F = k\frac{|q_1||q_2|}{r^2} = (8.99 \times 10^9)\frac{(3 \times 10^{-6})(5 \times 10^{-6})}{(0.2)^2} F=(8.99×109)15×10120.04=(8.99×109)(3.75×1010)F = (8.99 \times 10^9)\frac{15 \times 10^{-12}}{0.04} = (8.99 \times 10^9)(3.75 \times 10^{-10}) F3.37 NF \approx 3.37\ \text{N}

The force is attractive (opposite charges).

Practice Questions

  1. 1. If the distance between two charges is tripled, by what factor does the force change?

    F1/r2F \propto 1/r^2. Factor = 1/32=1/91/3^2 = 1/9. The force decreases to one-ninth.

    2. Two identical conducting spheres carry +6 μC+6\ \mu\text{C} and 2 μC-2\ \mu\text{C}. They are touched and separated. What charge does each carry?

    Total charge = +6+(2)=+4 μC+6 + (-2) = +4\ \mu\text{C}. Each gets half: +2 μC+2\ \mu\text{C}.

    3. How many excess electrons are on a 4.8×1019 C-4.8 \times 10^{-19}\ \text{C} object?

    n=q/e=4.8×1019/1.6×1019=3n = q/e = 4.8 \times 10^{-19} / 1.6 \times 10^{-19} = 3 electrons.

    4. Three charges are in a line: +2 μC+2\ \mu\text{C} at x=0x = 0, 3 μC-3\ \mu\text{C} at x=1 mx = 1\ \text{m}, and +1 μC+1\ \mu\text{C} at x=2 mx = 2\ \text{m}. What is the direction of the net force on the middle charge?

    The 3 μC-3\ \mu\text{C} charge is attracted toward both positive charges. Force from +2 μC+2\ \mu\text{C} pulls left (toward x=0x=0) and force from +1 μC+1\ \mu\text{C} pulls right (toward x=2x=2). Since q1>q3q_1 > q_3 at equal distances, the net force is toward the left.

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Summary

  • Electric charge is conserved and quantized.
  • Coulomb's law: F=kq1q2/r2F = kq_1q_2/r^2 — inverse-square law.
  • Like charges repel; unlike charges attract.
  • The net force on a charge is the vector sum of all individual forces (superposition).

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