Entropy, Free Energy and Thermodynamic Favorability

Master entropy changes, Gibbs free energy, spontaneity, coupling reactions, and the relationship between ΔG and K for AP Chemistry.

# Entropy, Free Energy and Thermodynamic Favorability

AP Chemistry Unit 9 determines whether a reaction is thermodynamically favorable (spontaneous) using entropy and Gibbs free energy.


1. Entropy ($S$)

Measure of disorder/dispersal of energy. Units: J/(mol·K)

SgasSliquid>SsolidS_{gas} \gg S_{liquid} > S_{solid}

ΔS\Delta S increases when:

  • Solid → liquid → gas
  • More moles of gas produced
  • Dissolution
  • Higher temperature

ΔSrxn=S(products)S(reactants)\Delta S^\circ_{rxn} = \sum S^\circ(\text{products}) - \sum S^\circ(\text{reactants})


2. Gibbs Free Energy

ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S

ΔG\Delta G Spontaneity
< 0 Spontaneous (thermodynamically favorable)
= 0 At equilibrium
> 0 Non-spontaneous

Temperature Dependence

ΔH\Delta H ΔS\Delta S Spontaneity
+ Always spontaneous
Spontaneous at low T
+ + Spontaneous at high T
+ Never spontaneous

At crossover: T=ΔH/ΔST = \Delta H / \Delta S (convert units!)


3. $\Delta G$ and Equilibrium

ΔG=RTlnK\Delta G^\circ = -RT\ln K

  • ΔG<0K>1\Delta G^\circ < 0 \Rightarrow K > 1 (products favored)
  • ΔG>0K<1\Delta G^\circ > 0 \Rightarrow K < 1 (reactants favored)

Non-standard conditions: ΔG=ΔG+RTlnQ\Delta G = \Delta G^\circ + RT\ln Q


4. Coupled Reactions

A non-spontaneous reaction can be driven by coupling with a spontaneous one (add ΔG\Delta G values). Example: ATP hydrolysis driving biological processes.


5. Practice Questions

    1. Predict the sign of ΔS\Delta S for: 2H2O(l)2H2(g)+O2(g)\text{2H}_2\text{O}(l) \rightarrow 2\text{H}_2(g) + \text{O}_2(g)
    1. Calculate ΔG\Delta G^\circ for a reaction at 298 K with ΔH=50\Delta H = -50 kJ/mol, ΔS=+100\Delta S = +100 J/(mol·K).
    1. Above what temperature is a reaction with ΔH=+200\Delta H = +200 kJ/mol and ΔS=+500\Delta S = +500 J/(mol·K) spontaneous?
    1. Calculate KK from ΔG=10.0\Delta G^\circ = -10.0 kJ/mol at 298 K.
    1. Explain how coupling reactions makes thermodynamically unfavorable processes occur in cells.

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Summary

  • ΔSrxn=S(prod)S(react)\Delta S_{rxn} = \sum S(\text{prod}) - \sum S(\text{react})
  • ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S; spontaneous when ΔG<0\Delta G < 0
  • ΔG=RTlnK\Delta G^\circ = -RT\ln K
  • Non-standard: ΔG=ΔG+RTlnQ\Delta G = \Delta G^\circ + RT\ln Q
  • Coupled reactions: sum ΔG\Delta G to drive unfavorable processes

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