Kinetics and Rate Laws

Master rate laws, integrated rate laws, half-life, reaction mechanisms, Arrhenius equation, and catalysis for AP Chemistry.

# Kinetics and Rate Laws

AP Chemistry Unit 5 covers reaction rates quantitatively: rate laws, integrated rate laws, half-life, the Arrhenius equation, reaction mechanisms, and catalysis.


1. Rate Laws

Rate=k[A]m[B]n\text{Rate} = k[A]^m[B]^n

Determined experimentally (NOT from balanced equation). Compare initial rates to find orders.


2. Integrated Rate Laws

Order Integrated Law Linear Plot Half-Life
0 [A]=kt+[A]0[A] = -kt + [A]_0 [A] vs t t1/2=[A]02kt_{1/2} = \frac{[A]_0}{2k}
1 ln[A]=kt+ln[A]0\ln[A] = -kt + \ln[A]_0 ln[A] vs t t1/2=0.693kt_{1/2} = \frac{0.693}{k}
2 1[A]=kt+1[A]0\frac{1}{[A]} = kt + \frac{1}{[A]_0} 1/[A] vs t t1/2=1k[A]0t_{1/2} = \frac{1}{k[A]_0}

Plot all three; the one that gives a straight line indicates the order.


3. Arrhenius Equation

k=AeEa/RTk = Ae^{-E_a/RT} lnk=EaR1T+lnA\ln k = -\frac{E_a}{R}\cdot\frac{1}{T} + \ln A

Plot lnk\ln k vs 1/T1/T: slope = Ea/R-E_a/R, y-intercept = lnA\ln A

Two-point form: lnk2k1=EaR(1T11T2)\ln\frac{k_2}{k_1} = \frac{E_a}{R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right)


4. Reaction Mechanisms

  • Elementary step: single molecular event
  • Rate-determining step (RDS): slowest step
  • Rate law comes from the RDS (or steps up to and including RDS)
  • Intermediate: produced in one step, consumed in another (not in overall equation)
  • Catalyst: consumed and regenerated; lowers EaE_a

5. Catalysis

  • Homogeneous: same phase as reactants
  • Heterogeneous: different phase (usually solid catalyst, gas/liquid reactants)
  • Enzyme: biological catalyst (specific, lock-and-key)
  • Catalysts provide alternative pathway with lower EaE_a; don't change ΔH\Delta H or equilibrium position

6. Practice Questions

    1. Given rate data, determine the rate law and calculate k.
    1. A first-order reaction has k = 0.025 s⁻¹. Calculate the half-life and time for 90% decomposition.
    1. Plot ln[A] vs t is linear with slope −0.0050 min⁻¹. What is the order and rate constant?
    1. Ea=50E_a = 50 kJ/mol. By what factor does k increase from 300 K to 310 K?
    1. A mechanism has Step 1 (fast equilibrium) and Step 2 (slow). Derive the rate law.

Want to check your answers and get step-by-step solutions?

Get it on Google PlayDownload on the App Store

Summary

  • Rate law determined experimentally: Rate=k[A]m[B]n\text{Rate} = k[A]^m[B]^n
  • Integrated rate laws: linearise to determine order
  • First order: constant t1/2=0.693/kt_{1/2} = 0.693/k
  • Arrhenius: lnk\ln k vs 1/T1/T gives Ea/R-E_a/R as slope
  • RDS determines rate law; catalysts lower EaE_a

Ready to Ace Your AP chemistry?

Get instant step-by-step solutions to any problem. Snap a photo and learn with Tutor AI — your personal exam prep companion.

Get it on Google PlayDownload on the App Store