Acids, Bases and Aqueous Equilibria

Master pH, Ka and Kb, buffer solutions, Henderson-Hasselbalch, titration curves, and Ksp for AP Chemistry.

# Acids, Bases and Aqueous Equilibria

AP Chemistry Unit 8 covers acid-base equilibria quantitatively: pH calculations for strong/weak acids and bases, buffers, titrations, and solubility equilibria (Ksp).


1. pH Calculations

Strong acids: [H+]=[acid][\text{H}^+] = [\text{acid}]; pH = log[H+]-\log[\text{H}^+]

Strong bases: [OH]=[base][\text{OH}^-] = [\text{base}] (×2 for Ba(OH)₂); pOH = log[OH]-\log[\text{OH}^-]; pH = 14 − pOH

Weak acids: Ka=[H+][A][HA]K_a = \frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}; if KacK_a \ll c: [H+]Kac[\text{H}^+] \approx \sqrt{K_a \cdot c}

Weak bases: Kb=[OH][BH+][B]K_b = \frac{[\text{OH}^-][\text{BH}^+]}{[\text{B}]}

Ka×Kb=Kw=1.0×1014K_a \times K_b = K_w = 1.0 \times 10^{-14}


2. Buffers

Weak acid + conjugate base (or weak base + conjugate acid)

Henderson-Hasselbalch: pH=pKa+log[A][HA]\text{pH} = pK_a + \log\frac{[\text{A}^-]}{[\text{HA}]}

Buffer capacity: larger amounts of weak acid and conjugate base → better buffering.

Effective buffer range: pKa±1pK_a \pm 1


3. Titration Curves

Key Points

  • Initial point: pH of acid/base alone
  • Buffer region: gradual pH change
  • Half-equivalence: pH = pKapK_a (for weak acid)
  • Equivalence point: moles acid = moles base; pH depends on salt hydrolysis
  • Post-equivalence: pH determined by excess titrant
Titration Equivalence pH
Strong-strong 7
Weak acid-strong base >7
Strong acid-weak base <7

4. Solubility Product ($K_{sp}$)

AB(s)A+(aq)+B(aq)\text{AB}(s) \rightleftharpoons \text{A}^+(aq) + \text{B}^-(aq) Ksp=[A+][B]K_{sp} = [\text{A}^+][\text{B}^-]

  • Q<KspQ < K_{sp}: unsaturated (no precipitate)
  • Q=KspQ = K_{sp}: saturated
  • Q>KspQ > K_{sp}: precipitate forms

Common ion effect: adding a common ion decreases solubility.


5. Practice Questions

    1. Calculate pH of 0.10 M acetic acid (Ka=1.8×105K_a = 1.8 \times 10^{-5}).
    1. A buffer contains 0.25 M NH₃ and 0.35 M NH₄Cl. Calculate pH (Kb=1.8×105K_b = 1.8 \times 10^{-5}).
    1. Sketch the titration curve for 0.10 M CH₃COOH with 0.10 M NaOH.
    1. Calculate molar solubility of PbCl₂ (Ksp=1.7×105K_{sp} = 1.7 \times 10^{-5}).
    1. Will a precipitate form if 50 mL of 0.010 M Pb²⁺ is mixed with 50 mL of 0.010 M Cl⁻? (Ksp=1.7×105K_{sp} = 1.7 \times 10^{-5})

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Summary

  • Strong acids/bases: direct [H⁺] or [OH⁻]
  • Weak acids: use KaK_a and ICE table
  • Buffers: pH=pKa+log([A]/[HA])\text{pH} = pK_a + \log([\text{A}^-]/[\text{HA}])
  • Titrations: identify key points (initial, half-equiv, equiv, post-equiv)
  • KspK_{sp}: compare Q to predict precipitation

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