Integration Techniques

AP Calculus BC guide to integration techniques: u-substitution, integration by parts, partial fractions, and trigonometric integrals.

# Integration Techniques — AP Calculus BC

AP Calculus BC requires integration techniques beyond basic antiderivatives and u-substitution. You must master integration by parts, partial fractions, and recognize which technique to apply.

Key Concepts

U-Substitution (Review)

∫f(g(x))g′(x) dx=∫f(u) du\int f(g(x))g'(x)\,dx = \int f(u)\,du where u=g(x)u = g(x).

Integration by Parts

∫u dv=uv−∫v du\int u\,dv = uv - \int v\,du

LIATE priority for choosing uu: Logarithmic, Inverse trig, Algebraic, Trigonometric, Exponential.

Common patterns:

  • ∫xex dx\int x e^x\,dx: u=xu = x, dv=ex dxdv = e^x\,dx.
  • ∫x2sin⁡x dx\int x^2 \sin x\,dx: apply by parts twice.
  • ∫ln⁡x dx\int \ln x\,dx: u=ln⁡xu = \ln x, dv=dxdv = dx.

Partial Fractions

For ∫P(x)Q(x) dx\int \frac{P(x)}{Q(x)}\,dx where degree of P<P < degree of QQ:

  1. Factor the denominator.
  2. Decompose into partial fractions.
  3. Integrate each fraction.

Example: 1(x−1)(x+2)=Ax−1+Bx+2\frac{1}{(x-1)(x+2)} = \frac{A}{x-1} + \frac{B}{x+2}.

Trigonometric Integrals

  • ∫sin⁡mxcos⁡nx dx\int \sin^m x \cos^n x\,dx: use identities or substitution.
  • Useful identities:
    • sin⁡2x=1−cos⁡2x2\sin^2 x = \frac{1 - \cos 2x}{2}
    • cos⁡2x=1+cos⁡2x2\cos^2 x = \frac{1 + \cos 2x}{2}

Improper Integrals (BC-specific)

∫a∞f(x) dx=lim⁡b→∞∫abf(x) dx\int_a^\infty f(x)\,dx = \lim_{b \to \infty} \int_a^b f(x)\,dx

∫abf(x) dx where f has a vertical asymptote\int_a^b f(x)\,dx \text{ where } f \text{ has a vertical asymptote}

Convergent if the limit exists and is finite; divergent otherwise.

Worked Example

Problem: Evaluate ∫xln⁡x dx\int x\ln x\,dx.

Solution: By parts: u=ln⁡xu = \ln x, dv=x dxdv = x\,dx. So du=dx/xdu = dx/x, v=x2/2v = x^2/2.

∫xln⁡x dx=x22ln⁡x−∫x22⋅1x dx=x22ln⁡x−12∫x dx\int x\ln x\,dx = \frac{x^2}{2}\ln x - \int \frac{x^2}{2} \cdot \frac{1}{x}\,dx = \frac{x^2}{2}\ln x - \frac{1}{2}\int x\,dx =x22ln⁡x−x24+C= \frac{x^2}{2}\ln x - \frac{x^2}{4} + C

Practice Questions

  1. 1. ∫3(x−1)(x+2) dx\int \frac{3}{(x-1)(x+2)}\,dx

    3(x−1)(x+2)=1x−1−1x+2\frac{3}{(x-1)(x+2)} = \frac{1}{x-1} - \frac{1}{x+2}. ∫=ln⁡∣x−1∣−ln⁡∣x+2∣+C\int = \ln|x-1| - \ln|x+2| + C.

    2. ∫1∞1x2 dx\int_1^\infty \frac{1}{x^2}\,dx

    lim⁡b→∞[−1/x]1b=lim⁡(−1/b+1)=1\lim_{b \to \infty}[-1/x]_1^b = \lim(−1/b + 1) = 1. Convergent.

    3. ∫xe−x dx\int xe^{-x}\,dx

    By parts: u=xu=x, dv=e−xdxdv=e^{-x}dx. =−xe−x+∫e−xdx=−xe−x−e−x+C=−(x+1)e−x+C= -xe^{-x} + \int e^{-x}dx = -xe^{-x} - e^{-x} + C = -(x+1)e^{-x} + C.

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Summary

  • U-substitution for composite functions.
  • Integration by parts: ∫u dv=uv−∫v du\int u\,dv = uv - \int v\,du (use LIATE).
  • Partial fractions: decompose rational functions.
  • Improper integrals: take limits; check convergence.

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