# Mendelian Genetics and Inheritance Patterns
Gregor Mendel established the foundation of genetics through his work with pea plants. AP Biology requires understanding of Mendel's laws, non-Mendelian inheritance patterns, pedigree analysis, and statistical testing with chi-squared.
1. Mendel's Laws
Law of Segregation
- Each organism has two alleles for each gene (one from each parent)
- Alleles segregate during gamete formation — each gamete receives only ONE allele
- Basis: separation of homologous chromosomes in meiosis I
Law of Independent Assortment
- Genes on different chromosomes assort independently during meiosis
- Basis: random orientation of bivalents in metaphase I
- Exception: linked genes (on the same chromosome) tend to be inherited together
2. Patterns of Inheritance
Complete Dominance
- Heterozygote shows dominant phenotype only
- Monohybrid cross (Aa × Aa): 3:1 phenotypic ratio
- Test cross (Aa × aa): 1:1 ratio confirms heterozygosity
Incomplete Dominance
- Heterozygote shows intermediate phenotype
- Example: Red × White snapdragons → Pink ()
- F₂ ratio: 1:2:1 (red : pink : white)
Codominance
- Both alleles fully expressed in heterozygote
- Example: ABO blood groups — → Type AB (both A and B antigens present)
- Sickle cell: → both normal and sickle haemoglobin produced
Multiple Alleles
- More than two alleles exist in the population (individuals still have only 2)
- Example: ABO system has three alleles: , ,
3. Sex-Linked Inheritance
- Genes on the X chromosome show different patterns in males and females
- Males () express X-linked recessive alleles because they have only one X
- Example: Colour blindness ( = affected male; = carrier female)
- Reciprocal crosses give different results for sex-linked traits
4. Beyond Mendel
Epistasis
- One gene masks or modifies the expression of another
- Produces modified ratios (9:3:4, 12:3:1, 9:7, etc.)
- Example: Labrador coat colour — E gene controls pigment deposition; B gene determines colour
Polygenic Inheritance
- Multiple genes contribute to one phenotype
- Produces continuous variation (bell curve)
- Examples: height, skin colour, eye colour
Pleiotropy
- One gene affects multiple phenotypes
- Example: Sickle cell allele → sickle-shaped RBCs, anaemia, pain crises, malaria resistance
Environmental Effects
- Environment can influence gene expression
- Example: Hydrangea flower colour depends on soil pH; fur colour in Siamese cats depends on temperature
5. Pedigree Analysis
Autosomal Recessive
- Affected individuals often have unaffected parents (carriers)
- Appears in both sexes equally
- Skip generations pattern
Autosomal Dominant
- Affected individuals have at least one affected parent
- Does not skip generations (usually)
X-linked Recessive
- More males affected than females
- Affected father cannot pass to sons (sons get Y)
- Carrier mothers can have affected sons
6. Chi-Squared Test
Steps:
- State null hypothesis (): no significant difference between observed and expected
- Calculate expected values from predicted ratio
- Calculate
- Determine degrees of freedom = categories − 1
- Compare to critical value (p = 0.05)
- If < critical value → accept (results fit expected ratio)
- If > critical value → reject (significant difference)
Example
Cross Aa × Aa, observe: 850 dominant, 150 recessive (total 1000) Expected (3:1): 750 dominant, 250 recessive df = 1; critical value = 3.84. Since 53.33 > 3.84 → reject . Results do NOT fit a 3:1 ratio.
Worked Example
Question: In fruit flies, eye colour is X-linked. Red (R) is dominant over white (r). Cross a carrier female with a red-eyed male. What phenotypic ratio is expected? (3 points)
Solution:
Parents: ×
| (red ♀) | (red ♀, carrier) | |
| (red ♂) | (white ♂) |
Expected ratio: 3 red : 1 white. All females are red-eyed. 50% of males are red-eyed, 50% are white-eyed.
Practice Questions
- Distinguish between incomplete dominance and codominance. (2 points)
- Explain why X-linked recessive traits are more common in males. (2 points)
- A dihybrid cross (AaBb × AaBb) yields 590 A_B_, 200 A_bb, 195 aaB_, 15 aabb. Perform a chi-squared test against 9:3:3:1 (critical value at df=3 is 7.82). (4 points)
- Define epistasis and give an example. (2 points)
Answers
- In incomplete dominance, the heterozygote shows a blended/intermediate phenotype (e.g., red × white → pink). In codominance, the heterozygote shows both parental phenotypes simultaneously (e.g., → type AB blood with both A and B antigens).
Want to check your answers and get step-by-step solutions?
Summary
- Mendel's laws: segregation (alleles separate in meiosis I) and independent assortment (genes on different chromosomes).
- Inheritance patterns: complete dominance (3:1), incomplete dominance (1:2:1), codominance, sex-linkage.
- Non-Mendelian: epistasis, polygenic inheritance, pleiotropy, environmental effects.
- Chi-squared test: ; compare to critical value to evaluate ratios.
- Pedigree analysis: identify autosomal dominant/recessive and X-linked patterns.
